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3 years ago

1. outer planet 2. density

Physics

2 answers:

quester [9]3 years ago

8 0

Answer:

1. C. Gaseous, spherical, cleared its neighborhood - Outer Planet

2. F. Amount of matter in an object, in a given space - Density

3. E. Distance between any planet and the sun - Orbital Distance

4. A. Amount of matter in an object - Mass

5. B. Irregular rock orbiting between Mars and Jupiter - Asteroid

6. D. Amount of space an object takes up - Volume

mestny [16]3 years ago

6 0

$\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}$

1. Outer planets - c. gaseous, spherical, cleared its neighborhood.

2. Density - f. amount of matter in an object, in a given space.

3. Orbital distance - e. Distance between any planet and the sun.

4. Mass - a. Amount of matter in an object.

5. Asteroid - b. Irregular rock orbiting between mars and Jupiter.

6. Volume - d. amount of space an object takes up.

Thanks
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3 years ago

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3 years ago

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3 years ago

Irina finds an unlabeled box of fine needles, and wants to determine how thick they are. A standard ruler will not do the job, a

Vsevolod [243]

Answer:

$d=\frac{1.22\times 640\times 10^{-9}\times 21.7}{7.35\times 10^{-2}}=2305.21\times 10^{-7}m$

Explanation:

The expression which represent the first diffraction minima by a circular aperture is given by $d sin\Theta =1.22\lambda$ --------eqn 1

The angle through which the first minima is diffracted is given by $tan\Theta =\frac{y_1}{D}$ ---------eqn 2

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So from eqn 1 and eqn 2 we can write

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Now putting all these value in eqn 3

$d=\frac{1.22\lambda D}{y_1}$

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3 years ago

1. ____ outer planet 2. ____ density

1. outer planet 2. density