Answer:
See below.
Step-by-step explanation:
Alexi originally has $43 in his bank account and deposits $7 per week.
Week 1: $50
Week 2: $57
Week 3: $64
Week 4: $71
Week 5: $78
The pattern is that it increased $7 every week starting from $43.
A pattern rule would be: y = 7x + 43 where x represents the number of weeks.
<h3>Answer-</h3>
I think 11 is the median for the data.
Answer:
<em>Pool 1 leaks faster than pool 2.</em>
Step-by-step explanation:
<u>Rates of change</u>
The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.
We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.
To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:
15 minutes = 15/60 = 1/4 hours
20 minutes = 20/60 = 1/3 hours
Now compute both rates of change:
Pool 1:
Pool 2:
Comparing both ratios, it's clear pool 1 leaks faster than pool 2.
i’ll try to help.
angle 3 and angle 1 are congruent angles, so they both equal 75°.
angle 1 and angle 5 are corresponding angles, so they both equal 75°. (it’s bc they’re positioned the same.
soooo the answer to that is 75° for angle 5. (not really great at explaining) also hope that the answer is right it should be.
The perimeter is 35. If we were to change the width, which is one of the dimensions of the flower bed, The perimeter will change. This means that perimeter will no longer be 35. So in order to keep the perimeter as it is, if we change one dimension, we must also change the other. Let's solve for the length, using the formula to see how much the length changes from. p = 2l + 2w 35 = 2l + 2(15) 35 = 2l + 30 5 = 2l 2.5 = l We must increase the length from 2.5 feet. This is because decreasing one dimension will decrease the perimeter. But if we increase the other dimension as well, it will restore the perimeter to where is was initially.
