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3 years ago

13

Who can help me figure this one out!?

1 answer:

STatiana [176]3 years ago

4 0

First find the inverse function:
y = -x^2 + 2
y - 2 = -x^2
2 - y = x^2
x = (2 - y)^0.5
Therefore inverse: y = (2 - x)^0.5 [x < 2]
Then simply sub in four random values for x to give your answer (hint, for your x values, use 1, - 2, - 7 and - 14. These should yield nice integer values for y)

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What is the LCM of 8 and 14 using prime factorization

steposvetlana [31]

The lcm 2 .. You are welcome..

8 0

3 years ago

Jane had 27 stickers two weeks ago. She bought the same amount of stickers each day for these two weeks. Now she has 237 sticker

lesya [120]

Answer:

Jane bought 15 stickers per day.

Step-by-step explanation:

Given;

Total number of stickers Jane has = 237

Number of stickers 2 weeks ago = 27

To find : Number of stickers she bought each day for two weeks.

Solution,

Let the number of stickers she bought everyday be x.

∴ Number of stickers for 2 weeks = $14\times x=14x$

Now according to question,

Total number of stickers = Number of stickers 2 weeks ago + Number of stickers she bought for 2 weeks

$237=27+14x\\14x=237-27\\14x=210\\x=15$

Thus the number of stickers she bought everyday for 2 weeks is 15.

3 0

3 years ago

Find the value of each variable.<br>

V125BC [204]

Answer:

see explanation

Step-by-step explanation:

Using the exact values of the trigonometric ratios

sin60° = $\frac{\sqrt{3} }{2}$ , cos60° = $\frac{1}{2}$

sin45° = cos45° = $\frac{1}{\sqrt{2} }$

Using the sine ratio on the right triangle on the left

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{a}{4\sqrt{3} }$ = $\frac{\sqrt{3} }{2}$

Cross- multiply

2a = 4 $\sqrt{3}$ × $\sqrt{3}$ = 12 ( divide both sides by 2 )

a = 6

Using the cosine ratio on the same right triangle

cos60° = $\frac{adjacent}{hypotenuse}$ = $\frac{c}{4\sqrt{3} }$ = $\frac{1}{2}$

Cross- multiply

2c = 4 $\sqrt{3}$ ( divide both sides by 2 )

c = 2 $\sqrt{3}$

------------------------------------------------------------------------------------------

Using the sine/cosine ratios on the right triangle on the right

sin45° = $\frac{a}{b}$ = $\frac{6}{b}$ = $\frac{1}{\sqrt{2} }$

Cross- multiply

b = 6 $\sqrt{2}$

cos45° = $\frac{d}{b}$ = $\frac{d}{6\sqrt{2} }$ = $\frac{1}{\sqrt{2} }$

Cross- multiply

$\sqrt{2}$ d = 6 $\sqrt{2}$ ( divide both sides by $\sqrt{2}$ )

d = 6

------------------------------------------------------------------------------------------------

a = 6, b = 6 $\sqrt{2}$ , c = 2 $\sqrt{3}$ , d = 6

3 0

3 years ago

Which of these questions are true or false?

anygoal [31]

Answer:

1. False

2. True

3. True

4. True

Step-by-step explanation:

5 0

3 years ago

The last time andy went bowling he had a mean score of 158 per game.

ahrayia [7]

Yes.
473 + 161/4 = 634/4 = 158.5

8 0

3 years ago