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tiny-mole [99]
2 years ago
6

Do these pairs of values (x and y) represent two quantities that are

Mathematics
1 answer:
kifflom [539]2 years ago
8 0

Answer:

A

Step-by-step explanation:

Becuase 4 divided that number is 2

6 divided by 3 is 2

and so on

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Point V is on line segment UW, given VW = x + 7, UW = 3x - 9, and UV = 8, determine the numerical length of UW
krek1111 [17]

Answer:

The numerical length of UW is 27

Step-by-step explanation:

8 0
3 years ago
The product of x and the sum of 6 and 8 times the square of x
Vaselesa [24]

Answer:

x(6 + 8x²) or 6x + 8x³.

Step-by-step explanation:

"The square of x" can be represented by x² and 8 times that would be 8 * x² or 8x². The sum of 6 and 8x² can be represented by 6 + x² and the product of x and 6 + x² can be represented by x * (6 + 8x²) or x(6 + 8x²) which simplifies to 6x + 8x³.

7 0
3 years ago
Read 2 more answers
PLEASE HELP ITS AN EMERGENCYYYYYYYYYY!!!
lorasvet [3.4K]

Answer:

The value of k is 1.

Step-by-step explanation:

x – 1 is a factor of f(x)

This means that:

x - 1 = 0

x = 1

That means that when x = 1, y = 0. We use this to find the value of k.

f(x) = 3x^3 - 4x + k

3*1^3 - 4(1) + k = 0

3 - 4 + k = 0

k = 1

The value of k is 1.

5 0
3 years ago
Which is equivalent to the expression below? |-3|<br> O<br> 13<br> -1-31<br> O<br> 3
hichkok12 [17]
It’s 3, absolute value makes everything positive
4 0
3 years ago
Read 2 more answers
Question 1 (1 point)
olya-2409 [2.1K]

For this case we can propose a system of equations:

x: Let the variable that represents the number of small cookies

y: Let the variable that represents the number of large cookies

According to the statement we have:

x + y = 130\\2x + 3y = 310

We multiply the first equation by -2:

-2x-2y = -260

We have the following equivalent system:

-2x-2y = -260\\2x + 3y = 310

We add the equations:

-2x + 2x-2y + 3y = -260 + 310\\y = 50

We look for the value of the variable "x":

x = 130-y\\x = 130-50\\x = 80

Answer:

They sold 80 small cookies and 50 large cookies

6 0
3 years ago
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