The Hardy-Weinberg equation is as follows:


Where:
(convert all % to decimals)
p= homozygous dominant
q= homozygous recessive
pq= heterozygous
While you did not specify whether the 0.2 frequency was for dominant or recessive, we can still figure out the answer.
Using the 1st equation, we can solve for the other dominant/recessive frequency:
1-0.2=0.8
Meaning that:
p= 0.8 & q=0.2
If the heterozygouz frequency is 2pq, then it becomes a simple "plug & chug" sort of approach.
2(0.8)(0.2)= 2(0.16)= 0.32
So, the heterozygous frequency would be:
0.32
Hope this helps!
1) plants
2) sugar
3) all
4) sugar and oxygen
5) not putting fertilizer on the soil
6) glucose
Answer:
I think its Monosaccharide
Explanation:
Please let me know if this helped!
Answer: Stomata
Explanation:
Stomata are pores in the leaf that allow gas exchange where water vapor leaves the plant and carbon dioxide enters.