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3 years ago

Bella measured the heights of her corn stalks in centimeters. The heights are 81, 88, 69, 65. 87.

Mathematics

1 answer:

masya89 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

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3 years ago

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amid [387]

Answer: I got D i'm not sure if that right though..

Step-by-step explanation:

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3 years ago

In triangle QRS, QR is congruent to SR and RT bisects QS. What justification can you give for QRT congruent to SRT and give the

spayn [35]

<span>Since RT bisects QS, we have QT congruent to ST. Bisect means it cuts QS in half. The we have RT congruent to RT since it is the same. By SSS, we have triangle QRT congruent to triangle SRT since QT is congruent to ST, RT is congruent to RT, and QR is congruent to SR. Each side is congruent to its respective side in the other triangle and that is SSS (side, side, side).</span>

4 0

3 years ago

Read 2 more answers

Determine the above sequence converges or diverges. If the sequence converges determine its limit

marshall27 [118]

Answer:

This series is convergent. The partial sums of this series converge to $\displaystyle \frac{2}{3}$ .

Step-by-step explanation:

The $n$ th partial sum of a series is the sum of its first $n\!\!$ terms. In symbols, if $a_n$ denote the $n\!$ th term of the original series, the $\! n$ th partial sum of this series would be:

$\begin{aligned} S_n &= \sum\limits_{k = 1}^{n} a_k \\ &= a_1 + a_2 + \cdots + a_{k}\end{aligned}$ .

A series is convergent if the limit of its partial sums, $\displaystyle \lim\limits_{n \to \infty} S_{n}$ , exists (should be a finite number.)

In this question, the $n$ th term of this original series is:

$\displaystyle a_{n} = \frac{{(-1)}^{n+1}}{{2}^{n}}$ .

The first thing to notice is the ${(-1)}^{n+1}$ in the expression for the $n$ th term of this series. Because of this expression, signs of consecutive terms of this series would alternate between positive and negative. This series is considered an alternating series.

One useful property of alternating series is that it would be relatively easy to find out if the series is convergent (in other words, whether $\displaystyle \lim\limits_{n \to \infty} S_{n}$ exists.)

If $\lbrace a_n \rbrace$ is an alternating series (signs of consecutive terms alternate,) it would be convergent (that is: the partial sum limit $\displaystyle \lim\limits_{n \to \infty} S_{n}$ exists) as long as $\lim\limits_{n \to \infty} |a_{n}| = 0$ .

For the alternating series in this question, indeed:

$\begin{aligned}\lim\limits_{n \to \infty} |a_n| &= \lim\limits_{n \to \infty} \left|\frac{{(-1)}^{n+1}}{{2}^{n}}\right| = \lim\limits_{n \to \infty} {\left(\frac{1}{2}\right)}^{n} =0\end{aligned}$ .

Therefore, this series is indeed convergent. However, this conclusion doesn't give the exact value of $\displaystyle \lim\limits_{n \to \infty} S_{n}$ . The exact value of that limit needs to be found in other ways.

Notice that $\lbrace a_n \rbrace$ is a geometric series with the first term is $a_0 = (-1)$ while the common ratio is $r = (- 1/ 2)$ . Apply the formula for the sum of geometric series to find an expression for $S_n$ :

$\begin{aligned}S_n &= \frac{a_0 \cdot \left(1 - r^{n}\right)}{1 - r} \\ &= \frac{\displaystyle (-1) \cdot \left(1 - {(-1 / 2)}^{n}\right)}{1 - (-1/2)} \\ &= \frac{-1 + {(-1 / 2)}^{n}}{3/2} = -\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\end{aligned}$ .

Evaluate the limit $\displaystyle \lim\limits_{n \to \infty} S_{n}$ :

$\begin{aligned} \lim\limits_{n \to \infty} S_{n} &= \lim\limits_{n \to \infty} \left(-\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\right) \\ &= -\frac{2}{3} + \frac{2}{3} \cdot \underbrace{\lim\limits_{n \to \infty} \left[{\left(-\frac{1}{2}\right)}^{n} \right] }_{0}= -\frac{2}{3}\end{aligned}}_$ .

Therefore, the partial sum of this series converges to $\displaystyle \left(- \frac{2}{3}\right)$ .

8 0

3 years ago

Explain one of the theorems that you would use to find the zero of higher degree polynomial

Genrish500 [490]

The zeros of a function f(x) are the values of x that cause f(x) to be equal to zero
One of methods to find the zeros of polynomial functions is The Factor Theorem

It is used to analyze polynomial equations. By it we can know that there is a relation between factors and zeros.

let: f(x)=(x−c)q(x)+r(x)

If c is one of the zeros of the function , then the remainder r(x) = f(c) =0
and f(x)=(x−c)q(x)+0 or f(x)=(x−c)q(x)

Notice, written in this form, x – c is a factor of f(x)
the conclusion is: if c is one of the zeros of the function of f(x),
then x−c is a factor of f(x)

And vice versa , if (x−c) is a factor of f(x), then the remainder of the Division Algorithm f(x)=(x−c)q(x)+r(x) is 0. This tells us that c is a zero for the function.

So, we can use the Factor Theorem to completely factor a polynomial of degree n into the product of n factors. Once the polynomial has been completely factored, we can easily determine the zeros of the polynomial.

8 0

3 years ago