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Pavel [41]
3 years ago
5

En france en 1900 la taille moyennes des femmes etait de 1,54 m et celle des hommes de 1,66 m. Entre 1900 et 2010 ces tailles mo

yeness ont augmentes de 5,55 %
Mathematics
1 answer:
frez [133]3 years ago
3 0

Complete question :

En France, en 1900, la taille moyenne des femmes était de 1,54 m et celle des hommes de 1,66 m. Entre

1900 et 2010 ces tailles moyennes ont augmentées d'environ 5,55%.

Calculer, en mètres, l'arrondi au centième des tailles moyennes des femmes et des hommes en 2010.​

Répondre :

Femmes = 1,63

Hommes = 1,75 m

Explication étape par étape:

Étant donné que :

Taille moyenne en 1900:

Hommes = 1,66 m

Femmes = 1,54 m

Pourcentage d'augmentation de poids d'ici 2010 = 5,55%

1 + 5,55% = 1 + 0,0555 = 1,0555

D'où,

Taille des femmes en 2010:

1,0555 * 1,54 = 1,62547 = 1,63 m

Pour la taille des hommes en 2010:

1,0555 * 1,66 m = 1,75213 = 1,75 m

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Maru [420]

Answer:

<em>The zero of the line is (2,0)</em>

Step-by-step explanation:

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
andriy [413]

Answer:

The point that maximizes the objective function is (3,0)

Step-by-step explanation:

we have

Constraints:

x\geq 0\\y\geq 0\\-x + 3\geq y\\y\leq \frac{1}{3}x+1

Using a graphing tool

The feasible region is the shaded area

see the attached figure

The vertices of the feasible region are

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we know that

To find the point in the feasible region that maximizes the objective function, replace each ordered pair of vertices in the objective function and then compare the results.

The objective function is

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For (0,0) -----> C=5(0)-4(0)=0

For (0,1) -----> C=5(0)-4(1)=-4

For (1.5,1.5) -----> C=5(1.5)-4(1.5)=1.5

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Answer:

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