Answer:
![\sqrt[5]{t^3}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bt%5E3%7D)
Step-by-step explanation: ![a^{x/n} =\sqrt[n]{a^x}](https://tex.z-dn.net/?f=a%5E%7Bx%2Fn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%5Ex%7D)
Answer:
27 SUVs
Step-by-step explanation:
Let number of ordinary cars be x and SUVs be y
We can write 2 equations and use substitution to solve for the number of SUVs.
<u>"The number of ordinary cars is larger than the number of sport utility vehicles by 59.3%"- </u>
This means that 1.593 times more is ordinary cars (x) than SUVs (y), so we can write:
x = 1.593y
<u>"The difference between the number of cars and the number of SUVs is 16" - </u>
Since we know ordinary cars are "more", we can say x - y = 16
<em>We can now plug in 1.593 y into x of the 2nd equation and solve for y:</em>
<em>x - y = 16</em>
<em>1.593y - y = 16</em>
<em>0.593y = 16</em>
<em>y = 27 (rounded)</em>
<em />
<em>Hence, there are 27 SUVs</em>
The problem wants you to add both
Step-by-step explanation:
soh cah toa
that is the saying I use
we will use cah
c is cos
a is ajacent
h is hypotinuse
to find cos K we need to do
adjacent / hypotenuse
can you do that and write it in the comments
I would show it in decimals. Seeing it to show how close it is to one would make it a lot easier- 1/6= .16. 1/8=.125 and 1/3=.33 So looking at the decimals you can see how one would be bigger than the other
