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Stells [14]
3 years ago
10

This bottle contains 200 mL of liquid plant food. What is the best estimate of how much the bottle can hold when it is filled to

the FULL mark?
Mathematics
1 answer:
aev [14]3 years ago
5 0

Answer: 1,000 ml

Step-by-step explanation:

From the looks of it, the 200ml mark is about a fifth of the volume needed to get to the FULL mark.

If 200 is ¹/₅, the full mark will be;

= 200/ ¹/₅

= 1,000 ml

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How many cubic centimeters is 5 cubic meters.
tresset_1 [31]
The key to solving this question is first knowing how many cubic cm are in one cubic m:

The ratio is always 1000000 cubic cm in 1 cubic meter.

Knowing this, we calculate how many cubic cm are in 5 cubic meters!

<u>1000000 cubic cm </u>= <u>1 </u><span><u>cubic m</u>
      x </span>cubic cm           5 cubic m

x = 1000000 cubic cm x 5 cubic m ÷ 1 cubic m
x = 5<span>000000 cubic cm

Hope this helps!
Feel free to message me if you have any questions :)</span>
4 0
3 years ago
Read 2 more answers
TJ invested $4000 in a bond at a yearly rate of 2% for 30
slavikrds [6]

Answer:

2.5 years

Step-by-step explanation:

I = 200     T=200/4000 0.2  = 2.5 years

P= 4000

R = 2%  0.2

T = ?  

4 0
3 years ago
Ty
AlekseyPX

Answer:

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1

3

3

Step-by-step explanation: just cuz

8 0
3 years ago
Answer quick for brainliest
Verizon [17]

Answer:

y=-2x+4

Step-by-step explanation:

Hello there!

Using y=mx+b, -2 is the slope and 4 is the y-intercept.

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7 0
3 years ago
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$100 is invested at 12% per year. If the amount is compounded annually, write the total amount after 2 years in exponential func
Sladkaya [172]

Answer:

A = $100(1.12)^2

Step-by-step explanation:

The standard formula for compound interest is given as;

A = P(1+r/n)^(nt) .....1

Where;

A = final amount/value

P = initial amount/value (principal)

r = rate yearly

n = number of times compounded yearly.

t = time of investment in years

For this case;

P = $100

t = 2years

n = 1

r = 12% = 0.12

Substituting the values, we have;

A = $100(1+0.12)^(2)

A = $100(1.12)^2

7 0
3 years ago
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