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Alekssandra [29.7K]
3 years ago
14

Pls help me my dads gonna hit me if i dont get this done

Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0

Answer:

(I can't answer if its greater than, less than, or equal to because you didn't

specify the number I have to compare to)

2. \frac{35}{8}

3. greater than

4. \frac{1}{9}

5. \frac{1}{6}

6. \frac{4}{5}

Step-by-step explanation:

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Please help i can not fail this!!
ivann1987 [24]
No solution 
i got u fam
4 0
3 years ago
Read 2 more answers
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
The histograms show the number of new subscribers in one month by age group for three newspaper. which statement is best support
Iteru [2.4K]

Answer:

D

Step-by-step explanation:

there were three times as many new subscribers in the 20-29 and the 30-39 age groups combined for the chronicle than in the 20-29 age group for the times.​

3 0
3 years ago
Read 2 more answers
“ write all your answers with a positive exponent so your answer will be in the form of x^# or 1/(x^#)
gayaneshka [121]

Answer:

Step-by-step explanation:

5). \frac{1}{x^{-9}} = \frac{1}{\frac{1}{x^9} }

     = x^{9}

6). \frac{1}{x^{-2}}=\frac{1}{\frac{1}{x^2} }

      = x²

7). x^{-6}=\frac{1}{x^6}

8). \frac{1}{x^{-7}}=\frac{1}{\frac{1}{x^7} }

           = x^{7}

9). x^{-8}=\frac{1}{x^8}

10). \frac{1}{x^{-3}} = \frac{1}{\frac{1}{x^{3}}}

            = x³

7 0
3 years ago
At a sale, suits were sold for $116 each. This price was 58% of a suit's original price. How much did a suit originally cost?
Fudgin [204]
To find the original price first put the % into decimal form.

58% is 0.58.

Then divide the discounted price ($116) by the % in decimal form:

116 / 0.58

Original price is $200.00
4 0
3 years ago
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