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Yanka [14]
3 years ago
10

A. 36 B. 12 C. 80 D. 60 E. 48 F. 20

Mathematics
1 answer:
Art [367]3 years ago
6 0

Answer:

it's d because it's correct

Step-by-step explanation:

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What are some equivalent fractions for 4/8
Zanzabum

Answer:

1/2 8/16 6/12

Step-by-step explanation:

7 0
3 years ago
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Which function f (x) , graphed below, or g (x) , whose equation is g (x) = 3 cos 1/4 (x + x/3) + 2, has the largest maximum and
Leya [2.2K]

Answer:

g(x), and the maximum is 5

Step-by-step explanation:

for given function f(x), the maximum can be seen from the shown graph i.e. 2

But for the function g(x), maximum needs to be calculated.

Given function :

g (x) = 3 cos 1/4 (x + x/3) + 2

let x=0 (as cosine is a periodic function and has maximum value of 1 at 0 angle)

g(x)= 3 cos1/4(0 + 0) +2

    = 3cos0 +2

     = 3(1) +2

     = 3 +2

     = 5 !

7 0
3 years ago
Nine students made models of mars and its moons. The answer is 18. What’s the question?
VashaNatasha [74]

The answer would be "Nine students each make 2 models of Mars and its moons. How many models did they make in total?" Since the answer is 18 and there are 9 students (and also since 18 can be divided into 9), you can divide 18 and 9 to get 2. This makes sense because if each student makes 2 models (as stated), there'd be a total of 18 models (as stated in the question you gave). Hope this helped!


4 0
3 years ago
A recipe for lemonade calls for 1 cup of sugar and 5cups of water. How much sugar is used per cup of water?
umka2103 [35]
1/5th of a cup of sugar is used.
6 0
3 years ago
Read 2 more answers
HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0
3 years ago
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