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The sum will be:
sigma(i = 1 to infinity, 30*(2/5)^i)
->
Which is equal to 30/(3/5) = 50
sigma(i = 1 to infinity, 30*(2/5)^i)
->
Which is equal to 30/(3/5) = 50
Answer:
Step-by-step explanation:
Let's look at the prime factors of 210.
210 = 2 * 3 * 5 * 7
Since no factor appears more than once, this radical cannot be simplified.