Phosphorus has 5 valence
valence electrons is located to their group#
yes because of TAVE available valence electrons
Answer:
I cant see it im so sorry
Explanation:
IDK
A. 2 is the answer let me know if im wrong sorry if i am.
Answer:
2CO + O₂ → 2CO₂ ΔH = -566 kj
Explanation:
Given data:
Energy evolved when 1 mole of CO react = 283 Kj
Energy evolved when 2 mole of CO react = ?
Solution:
Chemical equation:
2CO + O₂ → 2CO₂
It is given when one mole of CO react with oxygen 283 KJ energy is produced.
When 2 mole react,
2 ×-283 kj = -566 kj
Thermal equation:
2CO + O₂ → 2CO₂ ΔH = -566 kj
Answer: Glycolysis is stimulated by a high concentration of fructose-2,6-bisphosphate, and the gluconeogenesis is stimulated by a low concentration of fructose-2,6-bisphosphate.
Explanation: Fructose-2, 6-bisphosphate (F2, 6P) is an allosteric activator of the key enzyme in the glycolysis cycle, phosphofructokinase (PFK). F2, 6P also acts as an inhibitor of fructose bisphosphate phosphatase (FBPase) in gluconeogenesis. The concentration of F2, 6P is governed by the balance between its synthesis and breakdown, catalysed by phosphofructokinase-2 (PFK-2) and fructose-bisphosphatase-2 (FBPase-2), respectively. These enzymes are found in a dimeric protein and are controlled by a phosphorylation/dephosphorylation mechanisms. Phosphorylation of the dimeric protein results in an increased concentration of FBPase-2, leading to a decreased concentration of F2, 6P, thus activating the gluconeogenesis cycle. The concentration of PFK-2 is increased when the dephosphorylation of the dimeric protein takes place, leading to the increased concentration of F2, 6P, thus stimulating glycolysis cycle.
