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dimaraw [331]
3 years ago
14

Why would a thunderstorm move slowly?

Chemistry
1 answer:
3241004551 [841]3 years ago
8 0
Very generally the snow storms occur over a much larger area than a thunderstorm and generally move much slower this is why it moves slow. 
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Compounds A and B react to form compounds C and D according to the equation: aA + bB → cC + dD. Under which conditions will the
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Answer: A. The reaction takes place in one step.

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Molecularity of the reaction is defined as the number of atoms, ions or molecules that must colloid with one another simultaneously so as to result into a chemical reaction.

Order of the reaction is defined as the sum of the concentration of terms on which the rate of the reaction actually depends. It is the sum of the exponents of the molar concentration in the rate law expression.

Elementary reactions are defined as the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical reaction.

aA=bB\rightarrow cC+dD

Rate=k[A]^a[B]^b

k= rate constant

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b = order with respect to B

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Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 264 mL .
gavmur [86]
The formula for density is:

D = m/v

We can use the formula to figure out the mass because we already know two of the three values (we are given the density and volume), so we only have to solve for <em>m. </em>If we plug our given values into the formula, we get:

2.70 = m / 264

Now, all we need to do is solve for <em>m</em>. The goal is to get <em>m</em> on one side of the equation, and all we have to do is multiply each side of the equation by 264:

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264 × 2.70 = m

m = 712.8

The mass of the piece of aluminum is 712.8 grams.
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Electrons are moving in energy levels around nucleus.

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