Answer:
A scientist measures the standard enthalpy change for the following reaction to be -139.5 kj :
h2(g) + c2h4(g)c2h6(g)
based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of c2h4(g) is _____ kj/mol
Explanation:
Hydrogen ΔHof (kJ/mol) ΔGof (kJ/mol) So (J/mol K)
H2 (g)
0
0
130.7
Carbon ΔHof (kJ/mol) ΔGof (kJ/mol) So (J/mol K)
C2H6 (g)
-84.7
-32.8
229.6
Charles's Law.
<u>V1</u><u> </u> = <u>V2</u>
T1 T2
V1 = 720 mL
T1 = 22°C
T2 = 106°C
V2 = ?
then,
<u>7</u><u>2</u><u>0</u><u> </u> = <u>V2</u><u> </u>
22 106
V2 = 3469 mL
we will use the root mean squared speed of oxygen formula
v= (3RT) / M
T= vM/3R
where
v =1.12x104 m/s; velocity
R= (8.31447 kg m2 s-2 K-1 mol-1) gas constant
M = 0.0319988 kg/mol; molar mass of oxygen
substituting the given values, we will get
T(K)= 14.37K or -258.78 C
Oxygen molecules speed of 1.12x104 m/s is at temperature -258.78C.
I think the slant would be called the tilt