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g100num [7]
2 years ago
9

Dan described two layers of Earth's atmosphere.

Chemistry
2 answers:
tester [92]2 years ago
6 0

Answer:

The layer A is the thermosphere and the layer B is the exosphere.

Explanation:

One of the five layers of the atmosphere of the Earth is called thermosphere. It is the fourth layer of the Earth's atmosphere and is situated below the exosphere and above the mesosphere. The thermosphere is the biggest layer of the Earth's atmosphere, and the charged particles found in the thermosphere makes it easier for long distance communication through radio.  

The exosphere is the topmost layer of the Earth's atmosphere, here the atmosphere merges with the interplanetary space and thins out. It is situated directly above the thermosphere. It is the layer, which distinguishes Earth's atmosphere from outer space.  

saul85 [17]2 years ago
4 0

There are following layers in earth atmosphere

a) Troposhere: the innermost layer or lowest part of atmosphere

b)stratosphere: next to troposhere

c)mesosphere:above stratosphere, here lowest temperature is observed

d)Thermosphere and Ionosphere: This layer allows long distance radio communication

e)Exosphere: this layer separates outer space from earth's surface.

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Anastaziya [24]

Answer/Explanation: A weight lifted vertically to acquire gravitational potential energy. A weight lifted vertically to acquire gravitational potential energy. If the force were to be removed, the object would fall back down to the ground and the gravitational potential energy would be transferred to kinetic energy of the falling object.

3 0
2 years ago
Read 2 more answers
A process uses 63,400 SCF/h of natural gas. What is the annual cost of natural gas used in the process?
artcher [175]

Explanation:

It is known that 1 SCF produces approximately 1000 Btu of thermal energy.

As it is not mentioned for how many hours the gas is used in this process. Therefore, we assume that the total number of hours natural gas used in this process are as follows.

        365 \times 24 = 8760 hours

Now, we will calculate the annual cost of natural gas used in the process as follows.

               8760 \times 63400

              = 555384000 SCF

Hence, annual cost of natural gas used in this process = loss of thermal energy

This will be equal to,  555384000 \times 1000

                           = 555,384,000,000 BTU

Thus, we can conclude that the annual cost of natural gas used in the process is 555,384,000,000 BTU.

4 0
3 years ago
Can you imagine a situation in which the reserve of a fuel might be increased?
Kamila [148]
The reserve of a fossil fuel might be increased if mining or extraction techniques improve so that more of fuel can be extracted for  a profit 
6 0
3 years ago
Read 2 more answers
student has calibrated his/her calorimeter and finds the heat capacity to be 14.2 J/°C. S/he then determines the molar heat capa
nika2105 [10]

Answer:

24.03 J/mol.ºC

Explanation:

For a calorimeter, the heat lost must be equal to the heat gained from water plus the heat gained from calorimeter, which has the same initial temperature as the water.

-Qal = Qw + Qc (minus signal represents that the heat is lost)

-mal*Cal*ΔTal = mw*Cw*ΔTw + Cc*ΔTc

Where m is the mass, C is the specific heat, ΔT is the temperature variation, al is from aluminum. w from water and c from the calorimeter. Cw = 4.186 J/gºC

-25.5*Cal*(22.7 - 100) = 99.0*4.186*(22.7 - 18.6) + 14.2*(22.7 - 18.6)

1971.15Cal = 1699.10 + 58.22

1971.15Cal = 1757.32

Cal = 0.89 J/g.ºC

The molar mass of Al is 27 g/mol

Cal = 0.89 J/g.ºC * 27 g/mol

Cal = 24.03 J/mol.ºC

6 0
3 years ago
100 POINTS!!!
mixas84 [53]

1) Area of one side of each cube

The area of one side of each cube can be calculated by multiplying the length times the width:

A=L\cdot W

where

L = length

W = width

For cube A: L=1 cm, W=1 cm

So the area is: A_A = (1)(1)=1 cm^2

For cube B: L=2 cm, W=2 cm

So the area is: A_B=(2)(2)=4 cm^2

For cube C: L=3 cm, W=3 cm

So the area is: A_C=(3)(3)=9 cm^2

2) Surface area of each cube

The surface area of a cube is given by the sum of the areas of all its faces. Since a cube has 6 identical faces, this means that the total surface area is equal to 6 times the area of one face:

A=6 A_1

where

A_1 is the area of one face of the cube

For cube A, the area of one face is A_A=1 cm^2

So the surface area of cube A is

A'_A = 6A_A=6(1)=6 cm^2

For cube B, the area of one face is A_B=4 cm^2

So the surface area of cube B is

A'_B = 6A_B=6(4)=24 cm^2

For cube C, the area of one face is A_C=9 cm^2

So the surface area of cube C is

A'_C = 6A_C=6(9)=54 cm^2

3) Volume of each cube

The volume of a cube is obtained by multiplying its length, its width and its height:

V=L\cdot W \cdot H

Where:

L = length

W = width

H = height

Moreover for a cube, all the sides have equal length, so L=W=H

So the volume can be rewritten as

V=L^3

For cube A: L = 1 cm

So the volume is V_A=(1 cm)^3 = 1 cm^3

For cube B: L = 2 cm

So the volume is V_B=(2 cm)^3 = 8 cm^3

For cube C: L = 3 cm

So the volume is V_C = (3 cm)^3 = 27 cm^3

4) Ratio surface area/volume for each cube

In this part, we have to calculate the ratio between surface area and volume of each cube:

r=\frac{A}{V}

where

A is the surface area

V is the volume

For cube A, we have:

A_A = 6 cm ^2 (surface area)

V_A=1 cm^3 (volume)

So the ratio for cube A is:

r=\frac{6}{1}=6

For cube B, we have:

A_B = 24 cm ^2 (surface area)

V_B=8 cm^3 (volume)

So the ratio for cube B is:

r=\frac{24}{8}=3

For cube C, we have:

A_C = 54 cm ^2 (surface area)

V_C=27 cm^3 (volume)

So the ratio for cube C is:

r=\frac{54}{27}=2

4 0
3 years ago
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