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2 years ago

Dan described two layers of Earth's atmosphere.

Chemistry

2 answers:

tester [92]2 years ago

6 0

Answer:

The layer A is the thermosphere and the layer B is the exosphere.

Explanation:

One of the five layers of the atmosphere of the Earth is called thermosphere. It is the fourth layer of the Earth's atmosphere and is situated below the exosphere and above the mesosphere. The thermosphere is the biggest layer of the Earth's atmosphere, and the charged particles found in the thermosphere makes it easier for long distance communication through radio.

The exosphere is the topmost layer of the Earth's atmosphere, here the atmosphere merges with the interplanetary space and thins out. It is situated directly above the thermosphere. It is the layer, which distinguishes Earth's atmosphere from outer space.

saul85 [17]2 years ago

4 0

There are following layers in earth atmosphere

a) Troposhere: the innermost layer or lowest part of atmosphere

b)stratosphere: next to troposhere

c)mesosphere:above stratosphere, here lowest temperature is observed

d)Thermosphere and Ionosphere: This layer allows long distance radio communication

e)Exosphere: this layer separates outer space from earth's surface.

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3 years ago

You are given 25.00 mL of an acetic acid solution of unknown concentration. You find it requires 35.75 mL of a 0.1950 M NaOH sol

oee [108]

Answer:

0.2788 M

1.674 %(m/V)

Explanation:

Step 1: Write the balanced equation

NaOH + CH₃COOH → CH₃COONa + H₂O

Step 2: Calculate the reacting moles of NaOH

$0.03575 L \times \frac{0.1950mol}{L} = 6.971 \times 10^{-3} mol$

Step 3: Calculate the reacting moles of CH₃COOH

The molar ratio of NaOH to CH₃COOH is 1:1.

$6.971 \times 10^{-3} molNaOH \times \frac{1molCH_3COOH}{1molNaOH} = 6.971 \times 10^{-3} molCH_3COOH$

Step 4: Calculate the molarity of the acetic acid solution

$M = \frac{6.971 \times 10^{-3} mol}{0.02500L} =0.2788 M$

Step 5: Calculate the mass of acetic acid

The molar mass of acetic acid is 60.05 g/mol.

$6.971 \times 10^{-3} mol \times \frac{60.05g}{mol} =0.4186 g$

Step 6: Calculate the percentage of acetic acid in the solution

$\frac{0.4186g}{25.00mL} \times 100\% = 1.674 \%(m/V)$

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3 years ago

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MariettaO [177]

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3 years ago

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Comparing the energy and particle motion of the four states of matter, rank them from most energy to least energy.

julsineya [31]

Answer:

I believe it's plasma, solid, liquid, gas.

Explanation:

<h2>plasma and solids consist of lots, one jumbled, one together. liquid is still quite a bit, and gas is everywhere but there isn't much in one.</h2>

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1 year ago