Answer:

Step-by-step explanation:
The width of rectangle is the diameter of the semi-circle part
Area of one semicircle is given by 
Total area of semi circle will be 
Substituting 74 m for d and
as 3.14 we obtain
Total area semi-circle=
Area of rectangle is given by the product of length and width
Rectangular area=
Total area of rectangular and semi-circles will be

Therefore, area of training field is 
Answer:
Write out the value of (2.52 x 10^5) divide by (4 x 10^-3)
standard form plzzz
Step-by-step explanation: