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anygoal [31]
3 years ago
12

How might a collision between Neptune and Halley's Comet affect Neptune's orbit?

Chemistry
1 answer:
AveGali [126]3 years ago
5 0

Answer:

It will mess up the orbit around the sun

Explanation:

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Use the reaction 1₂(s) = 12(g), AH = 62.4 kJ/mol, AS = 0.145 kJ/(mol-K), for
Sati [7]

The Reaction is spontaneous when temperature is 430 K. Hence, Option (C) is correct.

<h3></h3><h3>What is Spontaneous reaction ?</h3>

Reactions are favorable when they result in a decrease in enthalpy and an increase in entropy of the system.

When both of these conditions are met, the reaction occurs naturally.

Spontaneous reaction is a reaction that favors the formation of products at the conditions under which the reaction is occurring.

According to Gibb's equation:

ΔG = ΔH - TΔS

ΔG = Gibbs free energy

ΔH = enthalpy change  = +62.4 kJ/mol

ΔS = entropy change  = +0.145 kJ/molK

T = temperature in Kelvin

  • ΔG  = +ve, reaction is non spontaneous
  • ΔG = -ve, reaction is spontaneous
  • ΔG   = 0, reaction is in equilibrium

ΔH - TΔS = 0 for reaction to be spontaneous

T = ΔH / ΔS

Here,

T = 500K

Thus the Reaction is spontaneous when temperature is 500 K.

Learn more about Gibbs free energy here ;

https://brainly.in/question/13372282

#SPJ1

3 0
2 years ago
Can someone help me, please?
VikaD [51]
15. D is correct, exothermic reactions release heat

I am not sure about 16
7 0
3 years ago
What is the mass of a piece of iron if its density is 1.98 g/mL and its volume is 2.45 mL?
viktelen [127]

Answer:

4.858 g

Explanation:

Start with the formula

density = \frac{mass}{volume}

density = 1.98 g/mL

volume = 2.45 mL

mass = ??

rearrange the formula to solve for mass

(density) x (volume) = mass

Add in the substitutes and solve for mass

1.98 g/mL x 2.45 mL = 4.858 g

3 0
3 years ago
No spam or links! Thanks!
Monica [59]

Answer:

364 K or 91°C

Explanation:

Applying,

V₁/T₁ = V₂/T₂................ Equation 1

Where V₁ = Initial Volume, V₂ = Final volume, T₁ = initial Temperature, T₂ = final Temperature.

make T₂ the subject of the equation,

T₂ = V₂T₁/V₁................. Equation 2

From the question,

Given: V₁ = 375 mL, V₂ = 500 mL, T₁ = 0.0°C = (273+0) K = 273 K

Substitute these values into equation 2

T₂ = (500×273)/375

T₂ = 364 K

T₂ = (364-273) °C = 91 °C

5 0
3 years ago
How to separate water from a mixture of rice and peas? Please
svp [43]
Depending on the type of pea, the peas should come to the top as they are lighter and larger. Then just scoop or brush them off into another container. If you separate it into smaller batches and work them one by one, you should then find you get pure rice batches left which you can put in their own container.
8 0
3 years ago
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