Question

Which reaction will occur? 2NaBr I2 Right arrow. 2NaI Br2 2Fe Al2O3 Right arrow. 2Al Fe2O3 2AgNO3 Ni Right arrow. Ni(NO3)2 2Ag Pb Zn(C2H3O2)2 Right arrow. Zn Pb(C2H3O2)2.

Answer 1

The reaction that has been occurred will be $\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$.

The chemical reaction has been defined as the interaction of the reactant  molecules for the formation of the product. The changes have been taken place in the reactivity series and under specific conditions.

Reaction occur

The displacement reaction has been taken place based on the reactivity series. The more reactive element has been able to displace the less reactive element in the compound and form a new compound.

The following reactions have been analyzed as:

• $\rm 2\;NaBr\;+\;I_2\;\rightarrow\;2\;NaI\;+\;Br_2$

In the reaction, Br has been replaced by Iodine. The iodine has been less reactive than Br and thus will not form the compound.

Thus, this reaction will not occur.

• $\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$

In the reaction, Al has been replaced by Fe. The Fe is more reactive than Al. thus this reaction will occur.

• $\rm 2\;AgNO_3\;+\;Ni\;\rightarrow\;Ni(NO_3)_2\;+\;2\;Ag$

The nickel has been less reactive than Ag, and thus will not be able to form the product.

Thus, this reaction will not occur.

• $\rm Pb\;+\;Zn(C_2H_3O_2)_2\;\rightarrow\;Zn\;+\;Pb(C_2H_3O_2)_2$

The lead has been less reactive than Zn, and thus will not be able to form the product.

Thus, this reaction will not occur.

The reaction that has been occurred will be $\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$.

Learn more about reactivity series, here:

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