The answer is A i did this before hope this helps
It increases
The attractive force between the nucleus and the electrons INCREASES if the proton number increases while the number of energy levels remains constant.
Explanation:
Remember that protons carry a positive charge while electrons carry a negative charges. Unlike charges attract while like charges repel. An increase in the number of protons increases the positive charge of the atomic nucleus. This means that the force of attraction on the electron cloud of the atom increases.
This is why the atomic radius of atoms decreases across a period (from left to right) as the mass number of the atoms increase (while the number of electron orbitals remains the same across the period).
Learn More:
For more on the atomic radius check out;
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Answer:
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Answer : The value of equilibrium constant for this reaction at 262.0 K is 
Explanation :
As we know that,
where,
= standard Gibbs free energy = ?
= standard enthalpy = -45.6 kJ = -45600 J
= standard entropy = -125.7 J/K
T = temperature of reaction = 262.0 K
Now put all the given values in the above formula, we get:
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = -12666.6 J
R = gas constant = 8.314 J/K.mol
T = temperature = 262.0 K
K = equilibrium constant = ?
Now put all the given values in the above formula, we get:
Therefore, the value of equilibrium constant for this reaction at 262.0 K is
