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Tamiku [17]
3 years ago
5

1. Each month, the city of Accra generates an average of 28 pounds of waste. Assume the variable is approximately normally distr

ibuted and the standard deviation is 2 pounds. If a household is selected at random, find the probability of its generating between 27 and 31 pounds of waste per month. Draw a normal distribution curve to show the required region.
2. It is assumed that consumption C depends on income Y and that this relationship takes the form of the linear function C = a + bY. When Y is GH¢600, C is observed to be GH¢660. When Y is 1,000, C is observed to be GH¢900. What are the values of a and b in this function? Express C in terms of Y only. Find the consumption if a family’s income is GH¢1,200.
Mathematics
1 answer:
Molodets [167]3 years ago
7 0

1. Answer: given: an average of 28 pounds

a.

Find z values corresponding to 27 and 31:

z=%2827-28%29%2F2=-1%2F2=-0.5

z=%2831-28%29%2F2=3%2F2=1.5

Find the area between z+=+-0.5 and z=+1.5

Table E gives us an area of 0.9332-0.30=0.6247=> The probability is 62.47%

b.

Find z values corresponding to 30.2

z=%2830.2-28%29%2F2=2.2%2F2=1.1 Find the area to the right of z+=1.1

it gives you an area of 0.1357=> The probability is 13.57%

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Find the value of unknown angle x,y,z,a,b,c with reasons and full process​
Oduvanchick [21]

Answer:

Step-by-step explanation:

x = 70 degree (being vertically opposite angles)

y + 70 degree =180 degree (being linear pair)

y = 180 - 70

y = 110 degree

In triangle,

x + 60 + misssing angle = 180 degree (sum of interior angles of a triangle)

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A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as
mamaluj [8]

Answer:

The farmer have at first <u>202</u> chickens.

Step-by-step explanation:

Given:

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as ducks left.

Now, to find the chickens farmer have at first.

Let the chickens be x.

And, the ducks be y.

<em>As, the farmer had twice as many chickens as ducks on his farm.</em>

So, x=2y    ......(1)

<em>As, given the farmer after selling 166 chickens and ducks, he had half as many chickens as ducks left.</em>

According to question:

x-166=(y-29)\times \frac{1}{2}

x-166=\frac{y-29}{2}

Substituting the value of x from equation (1) we get:

2y-166=\frac{y-29}{2}

<em>By cross multiplying we get:</em>

4y-332=y-29

<em>Adding both sides 332 we get:</em>

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<em>Subtracting both sides by </em>y<em> we get:</em>

3y=303

<em>Dividing both sides by 3 we get:</em>

y=101.

Now, to get the number of chickens substituting the value of y in equation (1):

x=2y\\\\x=2\times 101\\\\x=202.

Therefore, the farmer have at first 202 chickens.

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