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dsp73
4 years ago
14

How many valence electrons are there in na?

Chemistry
2 answers:
tensa zangetsu [6.8K]4 years ago
6 0
It is one hope this helps
rodikova [14]4 years ago
4 0
Your answer would be 1. Hope this Helps!
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ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST
cluponka [151]

Answer:

Ernest Rutherford discovered the existence of a center of the atom.

Explanation:

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4 years ago
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Distance divided by time
son4ous [18]
150÷3=50

350÷4=87.5

(50+87.5)÷2

137.5÷2

=68.75
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3 years ago
How does the atomic radius of an element is related to its metallic character
Aneli [31]

Answer:

The large the atomic radius the more the metallic character of elements

Explanation:

The atomic radius is related to the metallic character in a way that the larger the atomic radius, the more metallic a body becomes.

Therefore, as we go down a group, metallic character increases.

  • Metallic character relies on the ability and willingness of an atom to share its valence electrons.
  • As the size of an atom becomes large, the more metallic it is and the more its metallic character.
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5 0
3 years ago
Based on the kinetic theory, which statement is true? Matter consists of only large molecules. Matter is made up of only charged
goldfiish [28.3K]

The kinetic theory  states that matter consists of particles in constant motion.

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3 years ago
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In the presence of CN-, Fe3 forms the complex ion Fe(CN)63-. The equilibrium concentrations of Fe3 and Fe(CN)63- are 8.5 x 10-40
aleksklad [387]

Answer:

Kf = 9.96x10⁴¹

Explanation:

When Fe³⁺ and CN⁻ are in water, complex Fe(CN)₆³⁻ is formed, thus:

Fe³⁺ + 6CN⁻ ⇄ Fe(CN)₆³⁻

Kf is defined as:

Kf = [Fe(CN)₆³⁻] / [Fe³⁺] [CN⁻]⁶

Equilibrium concentration of ions is:

[Fe(CN)₆³⁻] = 1.5x10⁻³M

[Fe³⁺] = 8.5x10⁻⁴⁰

[CN⁻] = [KCN] = 0.11M

Replacing in Kf expression:

Kf = [1.5x10⁻³M] / [8.5x10⁻⁴⁰] [ 0.11M]⁶

<h3>Kf = 9.96x10⁴¹</h3>

5 0
3 years ago
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