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sdas [7]
2 years ago
9

Write the configuration for electron: 4, 2, -1, +12

Chemistry
1 answer:
Alexxandr [17]2 years ago
4 0

Answer:

-1

Explanation:

electrons are negative

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How many grams of water can be produced when 8.73 moles of benzene (C6H6) react with excess oxygen?. . Unbalanced equation: C6H6
Alex_Xolod [135]
<span>2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
</span>
2 moles C6H6 -------------------- 6 moles H2O
8.73 moles C6H6 --------------- ( moles H2O)

( moles H2O) = 8.73 x 6 / 2

( moles H2O) = 52.38 / 2

= 26.19 moles of H2O

Molar mass H2O = 18.00 g/mol

1 mole -------------- 18.00 g
26.19 moles ----- ( mass of H2O)

mass of H2O = 26. 19 x 18.00 => 471.42 g of water

hope this helps!


7 0
4 years ago
M=100g V=5cm^3 what is the density?
Aleks [24]
D =  \frac{mass}{volume}  \\ D =  \frac{100}{5}  = 20  \frac{g}{cm^3}
5 0
4 years ago
If a scientist took a Geiger counter into a laboratory and measured a very high reading, this would indicate that
Sedaia [141]
<span>B. ionizing radiation is present.
This is the correct answer
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3 0
3 years ago
Read 2 more answers
Calculate the number of molecules in a deep breath of air whose volume is 2.15 L at body temperature, 37 ∘C, and a pressure of 7
Zinaida [17]
PV = nRT 
R = 0.0821 L * atm / mol * K 
(ideal gas constant) 

First, convert 735 torr to atm. Divide by 760. 
(1 atm = 760 torr) 

735 torr * 1 atm / 760 torr = 0.967 atm 
Then, convert 37 C to Kelvin. Just add 273. 
37 C = 310K 

n = PV / RT 
= (0.967)(2.07) / (0.0821)(310) 
= 0.0786 mol 

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7 0
3 years ago
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Calculate the volume in milliliters of 2.37M potassium hydroxide that contains 9.29g of solute.
astra-53 [7]

The volume in millilitres of 2.37M potassium hydroxide that contains 9.29g of solute is 70mL.

<h3>How to calculate volume?</h3>

Volume of a solution can be calculated from the molarity, which is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.

Molarity = no of moles ÷ volume

no of moles = mass ÷ molar mass

Molar mass of pottasium hydroxide (KOH) = 56.1056 g/mol

moles = 9.29g ÷ 56.1056 g/mol = 0.166moles

2.37 = 0.166/V

V = 0.166 ÷ 2.37

V = 0.07L

Volume in millilitres = 70mL

Therefore, 70mL is the volume of the pottasium hydroxide solution.

Learn more about volume at: brainly.com/question/861096

#SPJ1

3 0
2 years ago
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