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gulaghasi [49]
2 years ago
10

PLEASE HELP MOI I GIVE BRAINIEST

Chemistry
1 answer:
goldenfox [79]2 years ago
6 0

Answer:

If you had alot of winter gear and flash lights due to there being alot of storms  on mars and having a glass dome filled with o2 and food then you could have a chance of surviving

Explanation:

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A student wishes to prepare 25mL of 0.1M NaOH from 6M NaOH.
liraira [26]

Answer:

Na(OH)4

Explanation:

Look at the charges and add them up

Na(OH) Na(OH)

7 0
2 years ago
A metal (M) forms an oxide with the formula MO. If the oxide contains 7.17 % O by mass, what is the identity of the metal?
Nataly_w [17]

The metal is lead, Pb.

One unit of the oxide contains one atom of O (16.00 u).

∴ Mass of oxide = 16.00 u O × (100 u MO/7.17 u O) = 223.15 u MO

Mass of M = mass of MO – mass of O = 223.15 u -16.00 u = 207.2 u

The only element with an atomic mass of 207.2 u is lead (Pb) and the formula of the oxide is PbO.

7 0
3 years ago
one bottle of aspirin holds 250 tablets, each containing 150 mg of aspirin and sells for $2.95. Another bottle holds 125 tablets
AlladinOne [14]
I bottle:

250 * 150mg = 37500mg

If 37500mg ------- cost ------- <span> $2.95
so 1mg       ------- cost ------- x

x = 1mg*</span> $2.95 / 37500mg =  $7,87*10⁻⁵ 

II bottle

125 * 200mg = 25000mg

If 25000mg ---------- cost ---------- <span>$3.50
so 1mg       ---------- cost ---------- x

x = 1mg* </span>$3.50 / 25000mg = $0,00014=$1,4*10⁻⁴


$7,87*10⁻⁵  < $1,4*10<span>⁻⁴
</span>
1st bottle is better bargain cause 1mg of aspirin its cheaper than in 2nd.
7 0
3 years ago
If the energy difference between two electronic states is 214.68 kJ / mol , calculate the frequency of light emitted when an ele
atroni [7]

{\qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

Energy difference btween the two electronic states can be expressed as :

{ \qquad \sf  \dashrightarrow \: \Delta E = h\nu}

[ h = planks constant,{\: \nu }= frequency ]

\qquad \sf  \dashrightarrow \:214.68 = 39.79 \times 10 {}^{ - 14}  \times  \nu

\qquad \sf  \dashrightarrow \: \nu =  \cfrac{214.68}{39.79 \times 10 {}^{ - 4} }

\qquad \sf  \dashrightarrow \: \nu =  \cfrac{214.68}{39.79 }  \times 10 {}^{14}

\qquad \sf  \dashrightarrow \: \nu  \approx  5.395 \times10 {}^{14}  \:\:hertz

5 0
1 year ago
20 POINTS!!!!
Ksju [112]
I think A. is the answer
5 0
3 years ago
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