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gulaghasi [49]
2 years ago
10

PLEASE HELP MOI I GIVE BRAINIEST

Chemistry
1 answer:
goldenfox [79]2 years ago
6 0

Answer:

If you had alot of winter gear and flash lights due to there being alot of storms  on mars and having a glass dome filled with o2 and food then you could have a chance of surviving

Explanation:

You might be interested in
In which sample is the average kinetic energy of the particles the greatest?
tangare [24]
Temperature is a measurement of average kinetic energy of the particles in a sample which means that the sample with the highest temperature has the highest average kinetic energy of the particles.

That being said the answer would be 4) 10 mL of H2O (l) at 35 degrees Celsius since that sample has the largest temperature.

I hope this helps.  Let me know if anything is unclear.
6 0
3 years ago
A student carefully placed 15.6 g of sodium in a reactor supplied with chlorine gas. When the reaction was complete, the student
BabaBlast [244]

Answer:

24.09 grams of chlorine gas reacted.

Explanation:

2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)

Moles of sodium chloride = \frac{39.7 g}{58.5 g/mol}=0.6786 mol

According to reaction, 2 moles of  NaCl are formed from 1 mole chlorine gas.

Then 0.6786 moles of NaCl will be formed from;

\frac{1}{2}\times 0.6786 mole=0.3393 mol

Mass of 0.3393 moles of chlorine  gas:

0.3393 mol × 71 g/mol = 24.09 g

24.09 grams of chlorine gas reacted.

5 0
3 years ago
Be sure to answer all parts. Butane gas is compressed and used as a liquid fuel in disposable cigarette lighters and lightweight
Salsk061 [2.6K]

Answer:

The correct answer will be "4.60 g".

Explanation:

The given values are:

Volume of Butane = 7.96 mL

Density = 0.579 g/mL

As we know,

⇒  Mass \ of \ Butane = Density\times Volume

On putting the estimated values, we get

⇒                              =0.579\times 7.96

⇒                              =4.60 \ g

6 0
3 years ago
The empirical formula of the sugar glucose is ch2o. if the relative molecular mass of glucose is measured to be 180.16 g/mol the
ZanzabumX [31]

Answer:

18016

Explanation:

(empirical formula)n=molar mass

7 0
2 years ago
Students performed a procedure similar to Part II of this experiment (Analyzing Juices for Vitamin C Content) as described in th
Elan Coil [88]

Students performed a procedure similar to Part II of this experiment (Analyzing Juices for Vitamin C Content) as described in the procedure section. Given that molarity of DCP is 9.98x10-4 M, it took 16.34 ml of DCP to titrate 10 mL of sample.

Amount of ascorbic acid = 0.050 L sample (0.01634 L DCP/0.01 L sample)( 9.98x10-4 mol DCP/L DCP)(1 mol Ascorbic acid/ 1mol DCP)(176.124 g/mol)(1000mg/1g)= 14.36 mg ascorbic acid

8 0
3 years ago
Read 2 more answers
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