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gulaghasi [49]
3 years ago
10

PLEASE HELP MOI I GIVE BRAINIEST

Chemistry
1 answer:
goldenfox [79]3 years ago
6 0

Answer:

If you had alot of winter gear and flash lights due to there being alot of storms  on mars and having a glass dome filled with o2 and food then you could have a chance of surviving

Explanation:

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Calculate the quantity of energy required to change 8.22 mol of liquid water to steam at 100oc. the molar heat of vaporization o
Ainat [17]
Since  the water  is  at  100 degrees  then   it take  40.6 kj/mol   to  change 1  mole of  water at 100 degrees into  steam at  100  degrees
  the  moles  of water  8.22mol
since  one  mole  take 40.6kj/mol   8.22mol  will  be  =
8.22mol  x  40.6 kj/mol =333.732  kj
 
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3 years ago
Which of the following electron configurations for neutral atoms is correct?
geniusboy [140]
Argon: 1s22s22p63s23p6  is right answer,
8 0
3 years ago
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Take car traveling with constant speed travels at 150 km in 7200 a. what is the speed of the car?
Andrej [43]
<span>Find the speed of the car in which it travels at 150 km in 7200 seconds.
This is an easy question, you just need to follow the given formula as always.
Since the time and the distance is already given, we are now looking for the speed
=> time = 7200 seconds
=> distance = 150km</span><span>
d = speed x time
S = distance / time
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Thus, the car travels for about 0.021 km per seconds.

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5 0
3 years ago
What is the molarity of 200 mL of solution in which 2.0<br> molesof sodium bromide is dissolved?
vodomira [7]

Answer:

10 M

Explanation:

Molarity -

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

From the question,

V = 200mL

Since, 1L = 1000mL ,

1 mL = 0.001 L

Hence,

V = 200mL = 0.2 L

n = 2.0 mol

Hence, to calculate the molarity of the solution, the above formula can be used as -

M = n / V

M = 2.0 mol / 0.2 L = 10 M

8 0
3 years ago
Write word equation followed by chemical equation for the following reactions:a) iron with copper (ll) sulphate b) copper with s
8_murik_8 [283]

Answer:

Iron + copper(II) sulphate → iron sulphate + copper

Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)

copper + silver nitrate → copper nitrate + silver

Cu (s) + 2AgNO3 (aq) → Cu(NO3)2 (aq) + 2Ag (s)

3 0
3 years ago
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