I believe the correct answer from the choices listed above is option A. To correct her measurement to standard temperature and pressure (STP), she should <span>make a volume correction based on a higher temperature of 273 K. Hope this answers the question. Have a nice day.</span>
Chemical Change because if it would be a physical change the physic of the tea would look different but it doesn’t
830 mL. A 2.3 mol/L solution of CaCl2 has a volume of 830 mL
I am guessing that the concentration of your solution is 2.3 mol/L.
a) Moles of CaCl2
MM of CaCl2 = 110.98 g/mol
Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)
= 1.910 mol CaCl2
b) Volume of solution
V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution
= 830 mL solution
Answer:D. 9.1 mole Ar
Explanation:
364 g Ar x 1 mole Ar / 40 g Ar
= 9.1 moles Ar
mole=10 x 10⁻³ : 46 g/mol = 2.17 x 10⁻⁴
