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jarptica [38.1K]

2 years ago

7

A box weighing 10 N is 4 m away from the fulcrum. How much force must be applied 1 m away on the opposite end of the fulcrum in

order for the sides to be balanced? What is the actual mechanical advantage of the machine?

1 answer:

julia-pushkina [17]2 years ago

4 0

Answer: Socratic

Explanation: i’m not sure but you can use Socratic it’s a good app that helps

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Chandra is doing an experiment to find out which type of dog food her dog prefers. The following are the steps of her experiment

ELEN [110]

Answer:

A the type of dog food because it was different and every other thing was the same.

8 0

2 years ago

Calculate the wavelength in centimeters of radar energy at a frequency of 10 GHz. What is the frequency in gigahertz of radar en

konstantin123 [22]

Explanation:

(a) Frequency of radar energy, $f = 10\ GHz =10^{10}\ Hz$

The relation between frequency and wavelength is given by :

$c=f\lambda$

$\lambda=\dfrac{c}{f}$

$\lambda=\dfrac{3\times 10^8}{10^{10}}$

$\lambda=0.03\ m$

or

$\lambda=3\ cm$

(b) If wavelength, $\lambda=25\ cm=0.25\ m$

$c=f\lambda$

$f=\dfrac{c}{\lambda}$

$f=\dfrac{3\times 10^8}{0.25}$

$f=1.2\times 10^9\ Hz$

or

f = 1.2 GHz

Hence, this is the required solution.

7 0

2 years ago

A _______ is a series of waves that come ashore at interval 10-45 mintues

Nostrana [21]

Answer:

tsunami

Explanation:

A tsunami is a series of waves that come ashore at interval 10-45 mintues

3 0

2 years ago

As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arr

Natalija [7]

Answer:

a) F = 680 N, b) W = 215 .4 J , c) F = 1278.4 N

Explanation:

a) Hooke's law is

F = k x

To find the displacement (x) let's use the elastic energy equation

$K_{e}$ = ½ k x²

k = 2 $K_{e}$ / x²

k = 2 85.0 / 0.250²

k = 2720 N / m

We replace and look for elastic force

F = 2720 0.250

F = 680 N

b) The definition of work is

W = ΔEm

W = $K_{ef}$ - $K_{eo}$

W = ½ k ( $x_{f}$ ² - x₀²)

The final distance

$x_{f}$ = 0.250 +0.220

$x_{f}$ = 0.4750 m

We calculate the work

W = ½ 2720 (0.47² - 0.25²)

W = 215 .4 J

We calculate the strength

F = k $x_{f}$

F = 2720 0.470

F = 1278.4 N

6 0

2 years ago

A temperature of 273 K is the temperature at which water

xz_007 [3.2K]

<span>273 K is the freezing point of water and it is equal to 0 degrees Celcius ,In this change ,heat is released so as to gain the suitable temperature for freezing.273 K is just the Celsius scale but with being 0 but the same scale ,this number was arrived at because temperature comes from the motion of a substance's particles.</span>

5 0

2 years ago