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3 years ago

When do the heavier elements finally form? Give a few example.

Physics

1 answer:

andrew11 [14]3 years ago

5 0

Answer:

Some of the universe's heavier elements are created by neutron star collisions. ... Light elements like hydrogen and helium formed during the big bang, and those up to iron are made by fusion in the cores of stars. Some heavier elements like gallium and bromine need something more, such as a supernova.

Explanation:

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Sound waves are longitudinal waves that can travel through air. Would you expect sound waves to travel faster through a low-dens

Serjik [45]

Answer:

Sound waves travel faster in a low-density gas

Explanation:

First of all, let's remind that sound waves are pressure waves: they consist of oscillations of the particles in a medium, which oscillate back and forth along the direction of motion of the wave (longitudinal wave).

The speed of sound in an ideal gas is given by the equation

$v=\sqrt{\gamma \frac{p}{\rho}}$

where

$\gamma$ is the adiabatic index of the gas

p is the gas pressure

$\rho$ is the gas density

From the equation, we see that the speed of sound is inversely proportional to the square root of the density: therefore, the lower the density, the faster the sound waves.

So, sound waves will travel faster in a low-density gas.

6 0

3 years ago

A proton moves with a velocity of v with arrow = (3î − 5ĵ + k) m/s in a region in which the magnetic field is B with arrow = (î

Allisa [31]

Answer:

The magnitude of the magnetic force this particle experiences is $2.6\times10^{-9}\ N$ .

Explanation:

Given that,

Velocity v= (3i-5j+k) m/s

Magnetic field B=(i+2j-k) T

We need to calculate the value $\vec{v}\times\vec{B}$

$(\vec{v}\times\vec{B})=3i+4j+11k$

We need to calculate the magnitude of the magnetic force this particle experiences

Using formula of magnetic force

$\vec{F}=q(\vec{v}\times\vec{B})$

Put the value into the formula

$\vec{F}=1.6\times10^{-19}\times(3i+4j+11k)$

$\vec{F}=(4.8i+6.4j+1.76k)\times10^{-19}$

$|F|=2.6\times10^{-9}\ N$

Hence, The magnitude of the magnetic force this particle experiences is $2.6\times10^{-9}\ N$ .

7 0

3 years ago

A truck moves 60 km West, and then 80 km North, and then

stira [4]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Distance travelled by the truck is ~

$\boxed{240 \: \: km}$

And it's displacement is ~

$\boxed{0 \: \: km}$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

See the diagram in attachment for reference ~

Let O be the initial point, It travels 60 km towards west till point B and then 80 km towards north till point P and returns to initial point O in a straight line, now as we can observe here, it forms a right angled Triangle.

The measure of two legs is 60 km and 80 km, let's find the hypotenuse ~

According to Pythagoras theorem ~

hypotenuse² = sum of squares of other two legs

that is ~

$h {}^{2} = 60 {}^{2} + 80 {}^{2}$

${h}^{2} = 3600 + 640 0$

$h {}^{2} = 10000$

$h = \sqrt{10000}$

$h = \sqrt{100 \times 100}{}$

$h = 100 \: \: km$

So, the distance between the point A and O is 100 km

Now, The total distance is equal to the distance covered through actual path that is ~

60 km + 80 km + 100 km

240 km

And displacement is the distance between the final point and initial point, but since the truck returns to the point from where it started the journey, so the final and initial point is same therefore displacement is equal to 0.

4 0

3 years ago

The velocity of a 150 kg cart changes from 6.0 m/s to 14.0 m/s. What is the magnitude of the impulse that acted on it?

tensa zangetsu [6.8K]

M = 150 kg.

Final velocity, v = 14 m/s

Initial Velocity, u = 6 m/s

Impulse = <span> m(v - u)</span>

= 150*(14 - 6)

= 150*8 = 1200 kgm/s or 1200 Ns<span> </span>

3 0

3 years ago

When two stars are bound together gravitationally and orbit a common mass, they're known as

JulijaS [17]

When two stars are bound together gravitationally and orbit a common mass, theyre known as B. BINARY STARS.

3 0

3 years ago