Answer:
8.08 x 10^-5 m
Explanation:
A = 2 mm^2 = 2 x 10^-6 m^2
Total number of electrons, N = 9.4 x 10^18
time, t = 3 s
n = 5.8 x 10^28 electrons/ m^3
Current, i = Q / t = N x e / t = (9.4 x 10^18 x 1.6 x 10^-19) / 3 = 0.5 A
Let vd be the drift velocity.
i = n e A vd
0.5 = 5.8 x 10^28 x 1.6 x 10^-19 x 2 x 10^-6 x vd
vd = 2.7 x 10^-5 m/s
Distance traveled by the electrons = velocity x time
= vd x t = 2.7 x 10^-5 x 3 = 8.08 x 10^-5 m
Solve for acceleration:
<em>a</em> = (21.4 m/s - 33.8 m/s) / (4.7 s)
<em>a</em> ≈ -2.6 m/s²
Solve for force:
<em>F</em> = (1400 kg) <em>a</em> ≈ -3700 N
The minus sign tells you the force points in the opposite direction of the car's motion. Its magnitude is always positive, so <em>F</em> = 3700 N.
Answer:
a) m = 59.63 [kg]
b) Wm = 95.41 [N]
Explanation:
El peso de un cuerpo se define como el producto de la masa por la aceleración gravitacional. DE esta manera tenemos:
W = m*g
Donde:
m = masa [kg]
g = gravedad = 9.81 [m/s^2]
m = W / g
m = 585 / 9.81
m = 59.63 [kg]
Es importante aclarar que la masa se conserva independientemente de la ubicación del cuerpo en el espacio.
Por ende su masa sera la misma en la luna.
El peso en la luna se calcula como Wm y es igual a:
Wm = 59.63 * 1.6 = 95.41 [N]
Answer:
4363.3231 feets²
Explanation:
Given that :
Distance, r = 50 ft
θ = 200°
The arc length of area covered :
Arc length = θ/360° * πr²
Arc length = (200/360) * 50 ft ^2 * π
Arc length = 0.5555555 * 2500 * π
Arc length = 4363.3231 feets²
