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4vir4ik [10]
3 years ago
9

What is the scientific method describes as nonlinear

Chemistry
1 answer:
Phoenix [80]3 years ago
8 0
Scientists often repeat one or more steps several times.
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What volume of carbon dioxide is produced when 6.40 g of methane gas, CH4 (g), reacts with excess oxygen? All gases are at 35.0C
Mandarinka [93]

Answer:

V = 10.3 L

Explanation:

Given data:

Mass of methane = 6.40 g

Volume of CO₂ produced = ?

Temperature = 35°C (35+273 = 308 K)

Pressure = 100.0 KPa (100.0/101 = 0.98 atm)

Solution:

Chemical equation:

CH₄ +  2O₂        →       CO₂ + 2H₂O

Number of moles of CH₄:

Number of moles = mass/molar mass

Number of moles = 6.40 g/ 16 g/mol

Number of moles = 0.4 mol

Now we will compare the moles of CO₂ with CH₄.

         CH₄          :         CO₂

           1             :           1

        0.4            :         0.4

Volume of CO₂:

Formula:

PV = nRT

0.98 atm ×V = 0.4 mol ×0.0821 atm.L/mol.K ×  308 K

0.98 atm ×V = 10.11 atm.L

V = 10.11 atm.L /0.98 atm

V = 10.3 L

3 0
2 years ago
Fe2O3(s) + 3CO(g) ---> 2Fe(l) + 3CO2(g) Steve inserts 450. g of iron(III) oxide and 260. g of carbon monoxide into the blast
baherus [9]

Answer: Theoretical yield is 313.6 g and the percent yield is, 91.8%

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe_2O_3=\frac{450}{160}=2.8moles

\text{Moles of} CO=\frac{260}{28}=9.3moles

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(l)+3CO_2(g)

According to stoichiometry :

1 mole of Fe_2O_3 require 3 moles of CO

Thus 2.8 moles of Fe_2O_3 will require=\frac{3}{1}\times 2.8=8.4moles  of CO

Thus Fe_2O_3 is the limiting reagent as it limits the formation of product and CO is the excess reagent.

As 1 mole of Fe_2O_3 give = 2 moles of Fe

Thus 2.8 moles of Fe_2O_3 give =\frac{2}{1}\times 2.8=5.6moles of Fe

Mass of Fe=moles\times {\text {Molar mass}}=2.6moles\times 56g/mol=313.6g

Theoretical yield of liquid iron = 313.6 g

Experimental yield = 288 g

Now we have to calculate the percent yield

\%\text{ yield}=\frac{\text{Actual yield }}{\text{Theoretical yield}}\times 100=\frac{288g}{313.6g}\times 100=91.8\%

Therefore, the percent yield is, 91.8%

6 0
3 years ago
An electron confined in a one-dimensional box is observed, at different times, to have energies of 12 eV, 27 eV, and 48 eV. What
Fynjy0 [20]

Answer:

l=3.5*10^{-10}m

Explanation:

From the question we are told that:

1st Energy     E_1=12eV=4(3eV)

2nd Energy  E_2=27eV=9(3eV)

3rd Energy   E_3=48eV=16(3eV)

 

Generally the equation for Energy E for electron in one dimensional box at ground state E_0 is mathematically given by

  E_0=\frac{h}{8ml^2}

  E_0=\frac{h}{8ml^2}

Therefore Length a is mathematically given as

l=\sqrt{\frac{h^2}{8mE_0} }

l=\sqrt{\frac{(6.625*10^{-34})^2}{8(9.1*19^{-31}{(3eV(1.6*10^{-19}))}}

l=3.5*10^{-10}m

8 0
3 years ago
Look at the diagram below.
Kazeer [188]

Answer:

3rd statment

Explanation:

ray 1 and 2 are same vertical line

5 0
3 years ago
Read 2 more answers
Complete the statement<br>qxy- bxy+cxy= xy( )​
andrey2020 [161]

Answer:

xy (-b+c+q) is the answer to this

3 0
3 years ago
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