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3 years ago

What is the centripetal force for a roller coaster if the mass is 10 kg and the normal force is 25 N?

Physics

1 answer:

Alinara [238K]3 years ago

7 0

Answer:

Fc = 123 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

$Fnet = Fapp + Fg$

Where;

Fnet is the net force.

Fapp is the applied force.

Fg is the force due to gravitation.

Given the following data;

Normal force = 25N

Mass = 10kg

To find the centripetal force;

From the net force, we have the following formula;

Fc = N + mg

Where;

Fc is the centripetal force.

N is the normal force.

mg is the the weight of the object.

Substituting into the formula, we have;

Fc = 25 + 10(9.8)

Fc = 25 + 98

Fc = 123 Newton

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3 years ago

A piece of stone is thrown up from a height of 25 meters above the ground. after 2 seconds the stone reaches the highest point.

Natasha2012 [34]

Answer:

A. 19.6 m/s

B. 44.6 m

C. 5.0 s

D. -19.6 m/s

Explanation:

At the highest point, the stone's velocity is 0.

A. Given:

v = 0 m/s

t = 2 s

a = -9.8 m/s²

Find: v₀

v = at + v₀

0 = (-9.8)(2) + v₀

v₀ = 19.6 m/s

B. Given:

y₀ = 25 m

t = 2 s

v₀ = 19.6 m/s

a = -9.8 m/s²

Find: y

y = y₀ + v₀ t + ½ at²

y = 25 + (19.6)(2) + ½(-9.8)(2)²

y = 44.6 m

C. Given:

y₀ = 25 m

y = 0 m

v₀ = 19.6 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

0 = 25 + (19.6)t + ½(-9.8)t²

0 = 4.9t² − 19.6t − 25

t ≈ 5.0 s

D. Given:

v₀ = 19.6 m/s

a = -9.8 m/s²

t = 4 s

Find: v

v = at + v₀

v = (-9.8)(4) + 19.6

v = -19.6 m/s

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4 years ago

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Answer:

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Explanation:

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In the attachment we can see the representation of the three vectors

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3 years ago

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arlik [135]

Answer:

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Explanation:

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The period of revolution T is given as

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therefore,

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4 years ago