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3 years ago

Which area would have a bigger change in temperature throughout the day?

Physics

2 answers:

Radda [10]3 years ago

7 0

Answer:

an inland city

Explanation:

Coastal areas have moderate temperature because the land absorbs and radiates heat much faster than the sea. So, during the day cool air from the sea rush towards the land, and during the night cool air from the land rush towards the sea.

Studentka2010 [4]3 years ago

5 0

Answer:

an inland city

Explanation:

an inland city

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What would a series circuit be used for?

igor_vitrenko [27]

Answer:

Explanation:

a series circuit would be an odd choice to power a battery or light a lamp when a direct would be much more efficient, and it's not converting types of energy, so C is the best possible answer

6 0

3 years ago

A 1300 kg steel beam is supported by two ropes. (Figure

Dmitriy789 [7]

Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.

By Newton's second law,

the net horizontal force acting on the beam is

$R_1 \cos(110^\circ) + R_2 \cos(60^\circ) = 0$

where $R_1,R_2$ are the magnitudes of the tensions in ropes 1 and 2, respectively;

the net vertical force acting on the beam is

$R_1 \sin(110^\circ) + R_2 \sin(60^\circ) - mg = 0$

where $m=1300\,\rm kg$ and $g=9.8\frac{\rm m}{\mathrm s^2}$ .

Eliminating $R_2$ , we have

$\sin(60^\circ) \bigg(R_1 \cos(110^\circ) + R_2 \cos(60^\circ)\bigg) - \cos(60^\circ) \bigg(R_1 \sin(110^\circ) + R_2 \sin(60^\circ)\bigg) = 0\sin(60^\circ) - mg\cos(60^\circ)$

$R_1 \bigg(\sin(60^\circ) \cos(110^\circ) - \cos(60^\circ) \sin(110^\circ)\bigg) = -\dfrac{mg}2$

$R_1 \sin(60^\circ - 110^\circ) = -\dfrac{mg}2$

$-R_1 \sin(50^\circ) = -\dfrac{mg}2$

$R_1 = \dfrac{mg}{2\sin(50^\circ)} \approx \boxed{8300\,\rm N}$

Solve for $R_2$ .

$\dfrac{mg\cos(110^\circ)}{2\sin(50^\circ)} + R_2 \cos(60^\circ) = 0$

$\dfrac{R_2}2 = -mg\cot(110^\circ)$

$R_2 = -2mg\cot(110^\circ) \approx \boxed{9300\,\rm N}$

8 0

2 years ago

Is the distance a baseball travels in the air after being hit distance a baseball travels in the air after being hit a discrete

Nookie1986 [14]

Answer:

Continuous random variable

Explanation:

The distance that baseball travels after being hit is a random variable and it assume any real value defined on the sample space.

The distance is measurable and thus is continuous random variable because continuous variable cannot be counted but could be measured.

3 0

3 years ago

URGENT I WILL GIVE BRAINLIEST

Reil [10]

Weight : It is the gravitational attraction force on an object near its surface.

It is always measured in the unit of Newton(N)

it is given by the product of mass and acceleration due to gravity

$W = mg$

here we know that mass of the pig is m = 140 kg

also we know that acceleration due to gravity near the surface of earth is approximately g = 9.8 m/s/s

so here we know by above formula

$W = (140 kg)(9.8 m/s^2)$

$W = 1372 N$

so correct answer will be

4 0

3 years ago

How do the sizes of the inner planets (from the sun to the asteroid belt) compare to the sizes of the outer planets?

Oxana [17]

Answer:

The smaller, inner planets include Mercury, Venus, Earth, and Mars. The inner planets are rocky and have diameters of less than 13,000 kilometers. The outer planets include Jupiter, Saturn, Uranus, and Neptune. The outer planets are called gas giants and have a diameter of greater than 48,000 kilometers.

Explanation:

6 0

3 years ago