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Ipatiy [6.2K]
2 years ago
15

A student's work to solve an equation is shown.

Mathematics
1 answer:
aliya0001 [1]2 years ago
4 0

9514 1404 393

Answer:

  • incorrectly
  • one solution

Step-by-step explanation:

The third line of the solution is incorrect. It should be ...

  5x +2 = -5x +2

Then the one solution can be found:

  10x = 0 . . . . . . . . . add 5x-2 to both sides

  x = 0

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How do you find the vertex of a parabola..?
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3 years ago
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∠A and \angle B∠B are supplementary angles. If m\angle A=(7x+24)^{\circ}∠A=(7x+24) ∘ and m\angle B=(7x-26)^{\circ}∠B=(7x−26) ∘ ,
Arturiano [62]

Answer:

115degrees

Step-by-step explanation:

Given the following angles

m<A=(7x+24)°

m<B=(7x-26)°

Since both angles are supplementary, their sum will be 180 degrees

Taking the sum of the angles

m<A + m<B = 180

7x+24 + 7x - 26 = 180

14x - 2 = 180

14x = 180+2

14x = 182

x = 182/14

x = 13

get m<A

m<A = 7x+24

m<A = 7(13) + 24

m<A = 91 + 24

m<A  = 115

Hence the measure of angle m<A is 115degrees

4 0
2 years ago
How do you solve, 5 ^3x-4/25=625​
gtnhenbr [62]

Step-by-step explanation:

(5^3x*25-4)/25=625

125^3x-4=625*25

5^x-4=15625

5^x=15625-4

5^x=15621 I can't solved by me if there is only 15625 then the answer will be 6 because 5^6=15625 but there is -4 too

3 0
3 years ago
Which description is true about ​pre-image ABC​ and ​image A′B′C′​ ?
scoray [572]

Answer:

Option (C)

Step-by-step explanation:

From the graph attached,

In ΔABC and ΔA'B'C',

∠A ≅ ∠A'

∠B ≅ ∠B'

Therefore, ΔABC ~ ΔA'B'C'

Corresponding sides of these triangles will be proportional.

\frac{\text{AB}}{\text{A'B'}}=\frac{\text{BC}}{\text{B'C'}}=\frac{\text{AC}}{\text{A'C'}}=\frac{2}{6}

Therefore, ratio of the sides, AC : A'C' = 1 : 3 shows that image triangle A'B'C' is a dilated form of pre-image ABC with a scale factor of 3.

Option (C) will be the correct option.

7 0
3 years ago
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