Answer:
The points are: (16.12,0),(-8.12,0).
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots 
such that 
, given by the following formulas:
Distance between two points:
Suppose we have two points, 
and 
. The distance between them is given by:
Find all points on the x-axis that are 14 units from the point (4, -7).
Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).
The distance is 14. So
So 
The points are: (16.12,0),(-8.12,0).
You get the hypothenuse by doing √a²+b² = c
So....
![\sqrt{x^2+[3(x+1)]^2} = 25](https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%5E2%2B%5B3%28x%2B1%29%5D%5E2%7D%20%3D%2025)
Square both terms
x² + (3x+3)² = 625
x² + 9x² + 18x + 9 - 625 = 0
10x² + 18x - 616 = 0
x₁,₂ = (-b±√Δ)/2a
Δ = b²-4ac
You call a 10, b 18 and c -616
x1,2 = (-18±√18²-4*10*-616)/2*10
x1,2 = (-18±√324+24640)/20
x1,2 = (-18±√24964)/20
x1,2 = (-18<span>±158)/20
x1 = -18+158/20 = 140/20 = 7
x2 = (-18-158)/20 = -176/20 = -44/5
Pick the first solution
So one leg is 7 and the other is 3(7+1) = 3(8) = 24
Let's verify </span>√24²+7² = √576+49 = √625 = 25
In y = mx + b form, the slope is in the m position and the y int is in the b position
y = mx + b
y = 7x - 8
so ur slope is 7 and ur y int is -8
so ur answer is : slope = 7
Answer:
Since, the given solution is (2, 14). Therefore, 7x−y=0. Similarly, another equation can be−x+y=−2+14=12. Similarly, another equation can be−2x−y=−2(2)−14=18.
