A very quick way of solving this problem is to recognize and use the fact that a line parallel to 5x-2y=2 has an equation which is exactly the same as 5x-2y=2 except for the constant.
Replace that 2 (on the right side of the equation) with C, and x with -4, and y with -3:
5(-4)-2(-3)=C
and find C. C = -20 + 6 = -14.
Therefore, the equation of the line parallel to 5x-2y=2 passing thru the point (-4, -3) is 5x-2y= -14. Notice how only the constant changes.
Answer:
12-5=7
unless it's not a prank or a joke question
2j = .5k
Let j = 5
2(5) = .5k
10 = .5k
divide both sides by .5
20 = k
When j = 5 , k = 20
The line (x = 3) will be parallel to y axis, and intersects x - axis at point (3 , 0)
The coordinates of line's x - intercept is (3 , 0)
graph in attachment ~
