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aksik [14]
3 years ago
13

The Johnson family wants to start a college fund for their daughter Gabriella. They put $63, 000 into an account that grows at a

rate of 2.55% per year, compounded quarterly. Given the function G(t)= 63,000(1+ .0255/4)^ 4t, where G(t) represents the amount of money in the account t years after the account is opened, given that no more money is deposited into or withdrawn from the account.
Calculate the number of years it will take for the account to reach approximately $150,000, to the nearest hundredth of a year.
Mathematics
1 answer:
Rainbow [258]3 years ago
5 0

Answer:

<em>It will take approximately 34.13 years</em>

Step-by-step explanation:

The function G(t) below represents the amount of money in some account t years after the account is opened for The Johnson's daughter Gabriella:

G(t)= 63,000(1+ .0255/4)^ {4t}

It's required to find the number of years (t) it will take for the account to reach G(t)=150,000. We need to solve the equation:

63,000(1+ .0255/4)^ {4t}=150,000

Dividing by 63,000 and simplifying:

\displaystyle (1+ .0255/4)^ {4t}=\frac{150,000}{63,000}=2.38095

Taking logarithms:

\displaystyle \log(1+ .0255/4)^ {4t}=\log 2.38095

Applying logarithms property:

\displaystyle (4t) \log(1+ .0255/4)=\log 2.38095

Solving for t:

\displaystyle 4t =\frac{\log 2.38095}{\log(1+ .0255/4)}

\displaystyle t =\frac{\log 2.38095}{4\log(1+ .0255/4)}

Calculating:

\displaystyle t =\frac{0.37675}{0.01104}

\boxed{t \approx 34.13}

It will take approximately 34.13 years

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svetlana [45]

Answer:

a) <em>The equation</em> (10s + 8w) <em>represents </em><em>the </em><em>calories </em><em>Bridget </em><em>ate </em><em>on </em><em>Monday </em><em>and </em><em>the </em><em>equation</em> (20s + w) <em>represents </em><em>the </em><em>calories</em><em> </em><em>she </em><em>ate</em><em> </em><em>the </em><em>next </em><em>day.</em>

<em>b)</em><em> </em><em>The </em><em>number </em><em>of </em><em>calories</em><em> </em><em>in </em><em>each </em><em>strawberry</em><em> </em><em>is </em>4 <em>and </em><em>the </em><em>number </em><em>of </em><em>calories </em><em>in </em><em>each </em><em>vanilla</em><em> </em><em>wafer</em><em> cookie</em><em> </em><em>is </em>19. The solution is s= 4 and w = 19.

Step-by-step explanation:

For part A, Bridget ate 10 strawberries and 8 vanilla wafer cookies on Monday. Since the the number of calories in a strawberry is <em>s</em> and the number of calories in a vanilla wafer cookie is <em>w </em>, the number of calories Bridget ate on Monday is <em>10s + 8w</em><em>.</em><em> </em>The next day, Bridget ate 20 strawberries and 1 vanilla wafer cookie. Hence, the number of calories Bridget ate on the next day is 20s<em> + w</em>.

For part B,

we will create two different simultaneous equations.

Equation 1: 10s + 8w = 192

Equation 2: 20s + w = 99

We need to find one of the terms first to solve the other term. For this case, I will solve for w first.

Multiply the first equation by 2.

Equation 3: 20s + 16w = 192*2 = 384.

Now, subtract equation 2 from this new equation.

Equation 4:

(20s + 16w) - (20s + w) = 384 - 99

20s + 16w - 20s - w = 285

15w = 285

This leaves only w left and we can solve w.

w = 285 / 15 = 19

Now, we can solve for s using equation 2.

20s + 19 = 99

20s = 99-19 = 80

Hence,

s = 80/20 = 4

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