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nikdorinn [45]
3 years ago
15

What would a 64 ring size be in the US THANKSSSS​

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

10.75 would be a 64 ring size in the US

You might be interested in
Help with all please
seropon [69]

a) First, draw a graph. The x axis should be numbered: 0, 1, 2, 3, 4, 5, 6, 7, 8. Each number is the last digit of the year. For each year, there is one average score that has to be plotted. Number the y axis of the graph from 0-600, by increments of 50, or something around there. Now, with each year (each x value) place the dot as high as the average score. Repeat with all years. DO NOT draw a line to connect them. A scatter plot is a bunch of points that are not connected.

b) Use the form (y2-y1)/(x2-x1) where (x1,y1) (x2,y2) are any two points from 2001-2006. It does not matter which points, pick any, and assign each of the numbers x1,y1 and x2,y2. Plug it in to the equation, and simplify. This is your slope, also called m. Now plug m into the equation y-y1=m(x-x1) where y1 and x1 are the x and y coordinates of any point from 2001 to 2006. x and y dont have values themselves, they stay there. Now distribute the m into the parenthesis, add y1 to both sides (to cancel it out on the left), and you should be left with the same equation, but now in y=mx+b form. B is where the line crosses the y axis, so put a point on the vertical axis where b is. M is your slope, so every time you go to the right one number, go up M numbers. Draw another point. Repeat this until you can connect these new dots into a line. This line should be on the same graph as your other points, but might not touch all of the scatter plot points. That's still okay, just leave it as is.

c) Find the point where x=6 (meaning the year is 2006) on your line. Find the average test score for that year by seeing where the point lines up along the y axis (draw a straight line from the point to the left to see, if you have to). Take that number and add 1m (the m is the number you used in step B) to it. This predicts what the average score might be after 1 (that's why the 1 is there) year. This is a predicted value, and might not be perfectly correct!! Write/record how close this new, predicted, score is to the actual number, 515, which can be found on the scatter plot.

d) repeat step C exactly as before (still use the year 2006) , but add 4m instead of 1m, to get the predicted score 4 years after 2006 (2010), instead of 1 year after (2007).

I hope I have been of some help! Best of luck!!! :)

3 0
3 years ago
What is Q1 AND Q3 AND IQR OF THE NUMBERS<br>2,12,52,33,8,14
Sedaia [141]
It is 25.

Q1 is 8
Q3 is 33
7 0
3 years ago
Read 2 more answers
Which of the following statements about the polynomial function f(x)=x^3+2x^2-1
ch4aika [34]

x = -1

x =(1-√5)/-2= 0.618

x =(1+√5)/-2=-1.618

Step  1  :

Equation at the end of step  1  :

 0 -  (((x3) +  2x2) -  1)  = 0  

Step  2  :  

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  -x3 - 2x2 + 1  =   -1 • (x3 + 2x2 - 1)  

3.2    Find roots (zeroes) of :       F(x) = x3 + 2x2 - 1

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  -1.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        0.00      x + 1  

     1       1        1.00        2.00      

The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms

In our case this means that

  x3 + 2x2 - 1  

can be divided with  x + 1  

Polynomial Long Division :

3.3    Polynomial Long Division

Dividing :  x3 + 2x2 - 1  

                             ("Dividend")

By         :    x + 1    ("Divisor")

dividend     x3  +  2x2      -  1  

- divisor  * x2     x3  +  x2          

remainder         x2      -  1  

- divisor  * x1         x2  +  x      

remainder          -  x  -  1  

- divisor  * -x0          -  x  -  1  

remainder                0

Quotient :  x2+x-1  Remainder:  0  

Trying to factor by splitting the middle term

3.4     Factoring  x2+x-1  

The first term is,  x2  its coefficient is  1 .

The middle term is,  +x  its coefficient is  1 .

The last term, "the constant", is  -1  

Step-1 : Multiply the coefficient of the first term by the constant   1 • -1 = -1  

Step-2 : Find two factors of  -1  whose sum equals the coefficient of the middle term, which is   1 .

     -1    +    1    =    0  

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step  3  :

 (-x2 - x + 1) • (x + 1)  = 0  

Step  4  :

Theory - Roots of a product :

4.1    A product of several terms equals zero.  

When a product of two or more terms equals zero, then at least one of the terms must be zero.  

We shall now solve each term = 0 separately  

In other words, we are going to solve as many equations as there are terms in the product  

Any solution of term = 0 solves product = 0 as well.

Parabola, Finding the Vertex :

4.2      Find the Vertex of   y = -x2-x+1

For any parabola,Ax2+Bx+C,the  x -coordinate of the vertex is given by  -B/(2A) . In our case the  x  coordinate is  -0.5000  

Plugging into the parabola formula  -0.5000  for  x  we can calculate the  y -coordinate :  

 y = -1.0 * -0.50 * -0.50 - 1.0 * -0.50 + 1.0

or   y = 1.250

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = -x2-x+1

Axis of Symmetry (dashed)  {x}={-0.50}  

Vertex at  {x,y} = {-0.50, 1.25}  

x -Intercepts (Roots) :

Root 1 at  {x,y} = { 0.62, 0.00}  

Root 2 at  {x,y} = {-1.62, 0.00}  

Solve Quadratic Equation by Completing The Square

4.3     Solving   -x2-x+1 = 0 by Completing The Square .

Multiply both sides of the equation by  (-1)  to obtain positive coefficient for the first term:

x2+x-1 = 0  Add  1  to both side of the equation :

  x2+x = 1

Now the clever bit: Take the coefficient of  x , which is  1 , divide by two, giving  1/2 , and finally square it giving  1/4  

Add  1/4  to both sides of the equation :

 On the right hand side we have :

  1  +  1/4    or,  (1/1)+(1/4)  

 The common denominator of the two fractions is  4   Adding  (4/4)+(1/4)  gives  5/4  

 So adding to both sides we finally get :

  x2+x+(1/4) = 5/4

Adding  1/4  has completed the left hand side into a perfect square :

  x2+x+(1/4)  =

  (x+(1/2)) • (x+(1/2))  =

 (x+(1/2))2

Things which are equal to the same thing are also equal to one another. Since

  x2+x+(1/4) = 5/4 and

  x2+x+(1/4) = (x+(1/2))2

then, according to the law of transitivity,

  (x+(1/2))2 = 5/4

We'll refer to this Equation as  Eq. #4.3.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (x+(1/2))2   is

  (x+(1/2))2/2 =

 (x+(1/2))1 =

  x+(1/2)

Now, applying the Square Root Principle to  Eq. #4.3.1  we get:

  x+(1/2) = √ 5/4

Subtract  1/2  from both sides to obtain:

  x = -1/2 + √ 5/4

Since a square root has two values, one positive and the other negative

  x2 + x - 1 = 0

  has two solutions:

 x = -1/2 + √ 5/4

  or

 x = -1/2 - √ 5/4

Note that  √ 5/4 can be written as

 √ 5  / √ 4   which is √ 5  / 2

Solve Quadratic Equation using the Quadratic Formula

4.4     Solving    -x2-x+1 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                     

           - B  ±  √ B2-4AC

 x =   ————————

                     2A

 In our case,  A   =     -1

                     B   =    -1

                     C   =   1

Accordingly,  B2  -  4AC   =

                    1 - (-4) =

                    5

Applying the quadratic formula :

              1 ± √ 5

  x  =    ————

                  -2

 √ 5   , rounded to 4 decimal digits, is   2.2361

So now we are looking at:

          x  =  ( 1 ±  2.236 ) / -2

Two real solutions:

x =(1+√5)/-2=-1.618

or:

x =(1-√5)/-2= 0.618

Solving a Single Variable Equation :

4.5      Solve  :    x+1 = 0  

Subtract  1  from both sides of the equation :  

                     x = -1

Hope this helps.

6 0
3 years ago
Please helpppp thank y’all
julsineya [31]

Answer:

105

Step-by-step explanation:

since its  a straight line it would add up to 180 degrees so 52 + 23 + 75 and you need 180 so 180-75 which gives 105 which is the missing angle

6 0
3 years ago
Read 2 more answers
Solving equations and Inequalities 1 ) -10p=2(p-12)
MArishka [77]
The answer is 2 = p
Explanation: Here the goal is to get the variable "p" by itself, so first your have to distribute 2 to (p-12) which gives you -10p = 2p-24. Then you add 10p on both sides so that the variable is on one side. Then you add 24 to both sides. After that you divide 12 from both sides, giving you 2 = P

-10P = 2(p-12)
-10p = 2p-24
+10p +10p
0 = 12p-24
+24 +24
24 = 12p
24÷12 = 12p÷12
2 = p
5 0
3 years ago
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