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Elanso [62]
3 years ago
7

The table below shows the hourly temperatures, for a city in Ohio on February 10, 2012, as predicted by the weatherman at the lo

cal news station at certain times since 10 a.m..
Table

write an equation for the curve of best fit.

Predict the temperature at 7:00p.m.

Mathematics
2 answers:
Kitty [74]3 years ago
5 0

Answer:

30

Step-by-step explanation:

30

bekas [8.4K]3 years ago
3 0

Answer:

Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool.

Step-by-step explanation:

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Scorpion4ik [409]
<span>Let A = the area of the whole circle
Let S = the area of the shaded portion</span><span>
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3 0
3 years ago
Which statement is true?
Ilia_Sergeevich [38]

Answer:

All squares are rectangles. Rectangles have 4 right angles. Therefore, all squares have 4 right angles.

Step-by-step explanation:

The old math saying: "Every square is a rectangle, but not all rectangles are squares."

What makes a rectangle a rectangle is that it has four right angles.

A square also has four right angles. Therefore, a square is a type of rectangle.

<h3>What makes the other answers wrong:</h3>

A rectangle does not have equal lengths on all four sides like a square does.

A square MUST have four right angles for it to be a square.

<em>Brainiliest Appreciated. </em>

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3 years ago
For the given angle measure, find the measure of a supplementary angle and the measure of a complementary angle, if possible. If
8090 [49]

Answer:

A complementary angle is 63 degrees and supplementary angle is 153 degrees.

Step-by-step explanation:

Complementary angle:

A complementary angle adds up to 90 degrees, so you have to subtract 27 from 90.  90-27=63

Supplementary angle:

A supplementary angle adds up to 180 degrees, so you have to subtract 27 from 180. 180-27=153

6 0
3 years ago
Write the exact value of 0.428x2.75
bonufazy [111]

the exact value of 0.428x2.75 is 1.177, in order to get this you multiply both number with each other.

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