Answer:
i think the answer is <u><em>115</em></u>
i am not sure tho..
its not 115
44x is the way the points are calculated. In order to find out the amount of questions there needs to be a constant, 10 which represents the number of wrong questions, and a variable, x which represents the number of correct questions. You have to know that if wrong questions were counted, he would have 440 points just for the 10 wrong questions. Next you have to add the amount of correct questions and their corresponding points. The numbers that you get should be put together with the wrong questions. The points for the wrong questions don't count but the questions do. When you find the number, (I don't know what it is so I will use x but you will have to find out what it is) you will add x, the number of correct questions to the 10 incorrect questions and then you will have 10+x for the questions. You will need to use 44x to find out the number of points and once you have done that, you use this equation to average the points over the total questions: 44x/10+x
Answer:
what is cheese ravioli tell Martha to go to the grocery store and get some chef Boyardee ravioli
So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Answer:
A
Step-by-step explanation:
The velocity of a moving body is given by the equation:
Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.
And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.
We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:
By substitution:
Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:
Zero Product Property:
Now, by testing values for t<1, 1<t<4, and t>4, we see that:
So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.
Hence, our answer is A.
