Given that the two swimmers competed and Ursula's speed is 60 m/min while Andre's speed is 48 m/min. The distance that the Ursula will catch up with Andre will be:
distance=(relative speed)×(time)
relative speed=60-48=12 m/min
the two swimmers met at a distance of:
12×1
=12 meters
Answer:
Interquartile Range
Step-by-step explanation:
i think
Answer:
a) 8 x 10^3 or 8000
b) 8 x 10^-2 or .08
Explanation: Refer to a guide on rounding sig figs
Answer:
B)y = 3x^2 - 3x-18
Step-by-step explanation:
y = (3x – 9)(x + 2)
y = 3x*x+3x*2-9*x-9*2
y = 3x^2 +6x-9x-18
y = 3x^2 - 3x-18
