Answer:
x=2±16i![\sqrt{73}](https://tex.z-dn.net/?f=%5Csqrt%7B73%7D)
Step-by-step explanation:
1.) Using the PEMDAS distribute the
using the FOIL method
![(x-2)^2= x^2-4x+4](https://tex.z-dn.net/?f=%28x-2%29%5E2%3D%20x%5E2-4x%2B4)
2.) Distribute the -16 to (
)
![-16(x^2-4x+4)= -16x^2+64x-64](https://tex.z-dn.net/?f=-16%28x%5E2-4x%2B4%29%3D%20-16x%5E2%2B64x-64)
3.) Add the -25 to the equation
=0
4.) Since this isn't factor-able, you must use the quadratic formula,
and distrubute the numbers
a=-16 b=64 and c=-89
5.) Simplify the radical by finding the factors of -18688 that has a perfect root as one of the factors (which is -256 and 73).
![\sqrt{-18688} =\sqrt{-256*73} =16i\sqrt{73}](https://tex.z-dn.net/?f=%5Csqrt%7B-18688%7D%20%3D%5Csqrt%7B-256%2A73%7D%20%3D16i%5Csqrt%7B73%7D)
6.)Simplify the fraction
![\frac{-64(+ or -)16i\sqrt{73} }{-32} ={2}(+ or -)16i\sqrt{73}](https://tex.z-dn.net/?f=%5Cfrac%7B-64%28%2B%20or%20-%2916i%5Csqrt%7B73%7D%20%7D%7B-32%7D%20%3D%7B2%7D%28%2B%20or%20-%2916i%5Csqrt%7B73%7D)
7.) Your two roots are:
{2}(+ or -)16i\sqrt{73}
-4 = 6 + b equals -10=b
Your subtract 6 from both sides and that gives you -4-6 which is -10
-2/3a-6=12a
-6=12a+2/3a
-6=38/3a
3/38*-6=a
-18/38=a
a=-9/19
a=-0.47
Step-by-step explanation:
the triangle is an isosceles triangle hence the base angles are equal
sum of angles in a triangle is 180°, therefore, the top angle =180-(62+62)
the top angle =56°
h°= the top angle because alternate angles are equal
hence, h=56°