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likoan [24]
3 years ago
13

A solution that contains LESS solute than it can hold at a given temperature is

Chemistry
1 answer:
slega [8]3 years ago
8 0
That is called an unsaturated solution
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What is the solubility of nitrogen and calcium nitrate in cyclohexane?
Sav [38]
I don't know man hahahaha
8 0
3 years ago
Which energy position do electrons generally want to be in?
soldier1979 [14.2K]

Answer: the ground state

Explanation: when electron's are attracted to something, they typically rotate counter clockwise, in theory we can apply this to darwin, i recomend that book btw but counter clockwise goes to ground

4 0
3 years ago
I've been stuck with this for like an hour, please help.
solniwko [45]

Explanation:

Molar mass of Hg = 200.59g/mol.

Therefore Moles = Mass / Molar mass

= 100g / (200.59g/mol) = 0.499mol.

7 0
3 years ago
3. Suppose you wanted to design an experiment to test the composition of a mixture that includes sodium phenoxide (NaC6H5O). You
Liula [17]

Answer:

21.5mL of a 0.100M HCl are required

Explanation:

The sodium phenoxide reacts with HCl to produce phenol and NaCl in a 1:1 reaction.

To solve this question we need to find the moles of sodium phenoxide. These moles = Moles of HCl required to reach equivalence point and, with the concentration, we can find the needed volume as follows:

<em>Mass NaC6H5O:</em>

1.000g * 25% = 0.250g NaC6H5O

<em>Moles NaC6H5O -116.09g/mol-</em>

0.250g NaC6H5O * (1mol/116.09g) = 2.154x10⁻³ moles = Moles of HCl required

<em>Volume 0.100M HCl:</em>

2.154x10⁻³ moles HCl * (1L/0.100mol) = 0.0215L =

<h3>21.5mL of a 0.100M HCl are required</h3>
4 0
3 years ago
The current global population is 7.7 billion people, and the WHO estimates the minimum water need per person per day is 15 L. An
anygoal [31]

Answer:

a) The amount of freshwater available as groundwater, lakes and rivers, does not even reach one day the need for consumption for the current global population.  ( t = 5.489 E-13 day )

b) The annual terrestrial precipitation, reaches to sustain the drinking water needs for the current global population

Explanation:

Let P = 7.7 billion people = 7.7 E12 person

∴ water needed for the total population for one day:

⇒ water amount  = 7.7 E12 person * ( 15 L / person. day ) = 1.155 E14 L H2O /day

⇒ water amount = 1.155 E14 L H2O/day * 1 E1 Km² H2O / L H2O = 1.155 E15 Km² H2O/day * ( 365 day / year ) = 4.216 E17 Km²/year

∴ freshwater available:

freshwater = 6.34 E2 Km² H2O

how long will this water sustain the current population?

⇒ t = 6.34 E2 Km² * day / 1.155 E15 Km² = 5.489 E-13 day

this amount of freshwater does not even meet the need of the current global population.

∴ the annual terrestrial precipitation (Py) = 505000 Km³/year..........from literature

⇒ Py = 505000 Km³ H2O/year * ( 1000 m/Km )³ * ( 1000L/m³ )

⇒ Py = 5.05 E17 L H2O/year * ( 1 E1 Km² / L ) = 5.05 E18 Km² H2O/year

⇒ Py > water amount

the annual terrestrial precipitation of water, reaches to sustain the drinking water needs.

4 0
3 years ago
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