solution:
A = 192 x (1/2) ^ (15/5) = 192 x (1/2) ^3 = 192 x 1/8 = 24 mg
Starting by hitting acetylene with NaNH2 to deprotonate, this C-- will attack the C connected to the Br Sn2 style to lengthen the chain by two carbons.
Do this same thing again with the other CH of the acetylene and another bromoethaneto get a six carbon chain, namely, 3-hexyne.
Now, reduce the alkyne to an alkene via H2/Pd/C, and that gives 3-hexene.
Answer:
262.5 mL
Explanation:
21% of the 1.25 L volume is methanol, so the required amount of methanol is ...
0.21 × 1250 mL = 262.5 mL
Answer:
3 × 10¯¹⁰
Explanation:
9×10² ÷ 3×10¹²
The above expression can be evaluated as follow:
9×10² ÷ 3×10¹²
Recall:
3² = 9
3¹ = 3
Therefore,
9×10² ÷ 3×10¹² = 3²×10² ÷ 3¹×10¹²
Recall:
y^m ÷ y^n = y^(m – n)
Therefore,
3²×10² ÷ 3×10¹² = 3²¯¹ × 10²¯¹²
= 3¹ × 10¯¹⁰
Recall:
y¹ = y
Therefore,
3¹ × 10¯¹⁰ = 3 × 10¯¹⁰
Therefore,
9×10² ÷ 3×10¹² = 3 × 10¯¹⁰
The compounds
CH3OCH3 and CH3CH2OH have different functional groups. Therefore, these compounds
have different physical and chemical properties. CH3OCH3 is diethyl ether with
a functional group ether while CH3CH2OH is ethanol with a functional group
alcohol.
Answer:
The correct answer would be C) Support
