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Alina [70]
3 years ago
9

A ring, cylinder, solid sphere, and hollow sphere are all released from rest from the same height on an inclined surface, at the

same time. All four objects have uniform density, have the same mass, same radius, and roll without slipping.1. Which one has the largest total kinetic energy at the bottom?a) ringb) cylinderc) solid sphered) hollow spheree) they all reach the bottom with the same total kinetic energy2. Which one reaches the bottom last?a) ringb) cylinderc) hollow sphered) solid spheree) they all reach the bottom at the same time
Physics
1 answer:
crimeas [40]3 years ago
7 0

Answer:

Explanation:

  • The expression for acceleration of the rolling body on an inclined plane is given as a = gsinФ/1 + k²/R²
  • where Ф is the angle of inclination, R is the radius, k is the radius of gyration.
  • The potential energy of the system is given as ; PE = mgh
  • The potential energy will be constant for ring, cylinder, solid sphere, and hollow sphere.
  • The total kinetic energy of the rolling body is ; KE = mv²/2 + Iw²/2
  • Hence, the total kinetic energy of the ring, cylinder, solid sphere and hollow sphere will be constant.

2. The moment of inertia of the ring is given as ;

I = mR²

The moment of inertia of the ring is maximum and therefore reaches the bottom last.

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Suppose that a block of mass 2 kg is pulled to the right with a force of 10 N, and the friction force on the block is directed t
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Answer:

The block has an acceleration of 3 m/s^{2}

Explanation:

By means of Newton's second law it can be determine the acceleration of the block.

\sum F_{r} = ma   (1)

Where \sum F_{r} represents the net force, m is the mass and a is the acceleration.

F_{x} + F{y} = ma  (2)

The forces present in x are F = 10 N and f = 4 N (the friction force):

F_{x} = 10 N - 4 N

Notice that f subtracts to F since it is at the opposite direction.

F_{x} = 6 N

The forces present in y balance each other:

F_{y} = 0

Therefore:

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But 1 N = 1 Kg.m/s^{2} and writing (3) in terms of a it is get:

a = \frac{6 Kg.m/s^{2}}{2 Kg}  

a = 3 m/s^{2}

So the block has an acceleration of a = 3 m/s^{2}.

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