YAHOO ANSWERSA 1260 kg car moving south at 12.9 m/s collides with a 2430 kg car moving north. The cars stick together and move a
s a unit after the collision at a velocity of 4.38 m/s to the north. Find the velocity of the 2430 kg car before the collision.
1 answer:
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The given question is incomplete. The complete question is as follows.
A parallel-plate capacitor has capacitance = 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.
What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed V/m?
Explanation:
It is known that relation between electric field and the voltage is as follows.
V = Ed
Now,
Q = CV
or, Q =
Therefore, substitute the values into the above formula as follows.
Q =
=
=
Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is .
Answer:
x component 60.85 m
y component 101.031 m
Explanation:
We have given distance r = 118 km
Angle which makes from ground = 58.9°
(a) X component of distance is given by
(b) Y component of distance is given by
These are the x and y component of position vector