This one is fairly simple. The area of a rhombus is the same as that of a parallelogram, which is side * height. In this case, we have 6.5 (side) *3 (height) = 19.5 sq. inches. Hope this helps!

6 0

2 years ago

A dilation with a scale factor of 4 is applied to the three line segments shown. The resulting images are P'Q', A'B', and M'N' D

alexira [117]

Answer:

1st into the 3rd 2nd into 1st 3rd into 3rd

Step-by-step explanation:

8 0

2 years ago

Verify the identity. cotangent x equals StartFraction 1 plus cosine 2 x Over sine 2 x EndFractioncot x= 1+cos2x sin2x Use the ap

lutik1710 [3]

Answer with Step-by-step explanation:

We are given that

RHS

$\frac{1+Cos2x}{Sin2x}$

We have to verify the identity.

We know that

$1+Cos2x=2Cos^2 x$

$Sin2x=2SinxCos x$

Using the formula

$\frac{2Cos^2x}{2SinxCosx}$

$\frac{Cosx}{Sinx}$

$Cot x$

By using the formula

$Cotx=\frac{Cosx}{Sinx}$

LHS=RHS

Hence, verified

6 0

3 years ago