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forsale [732]
3 years ago
10

Help!!!!Given log7⁡3≈0.5646 and log7⁡16≈1.4248, evaluate the expressions.​

Mathematics
2 answers:
kolezko [41]3 years ago
7 0

Answer:noooo

Step-by-step explanation:

krok68 [10]3 years ago
3 0

Answer:

a)  0.356

b)  1.1397

Step-by-step explanation:

a) log₇2

  • log(2) / log(7)
  • 0.356

b) log₇ (¹⁴⁷/₁₆)

  • <u> log (¹⁴⁷/₁₆)</u>

         log (7)

  • 1.1397
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Math help Please!!!!
GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation  −2y=3x+7 in the form y=-\dfrac{3}{2}x-\dfrac{7}{2}. Here the slope of the given line is  m_1=-\dfrac{3}{2}. If m_2 is the slope of perpendicular line, then

m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.

Answer 1: \dfrac{2}{3}

Part B. The slope of the line y=−2x+3 is -2. Since -\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2, then lines from part A are not parallel to line a.

Since -2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1, both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line y=\dfrac{x}{4}+5 is \dfrac{1}{4}. Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then

7=-4·2+b,

b=7+8,

b=15.

Answer 4: y=-4x+15.

Part E. Consider vectors \vec{p}_1=(-c-0,0-(-d))=(-c,d)\quad \text{and}\quad \vec{p}_2=(0-b,a-0)=(-b,a). These vectors are collinear, then

\dfrac{-c}{-b}=\dfrac{d}{a},\quad \text{or}\quad -\dfrac{a}{b}=-\dfrac{d}{c}.

Answer 5: -\dfrac{a}{b}=-\dfrac{d}{c}.

5 0
3 years ago
Read 2 more answers
Write the polynomial in standard form.
sp2606 [1]

The standard form is:

4x^5+3x^2+3

Degree = 5, leading coefficient=4

The 5th degree polynomial is:

Quintic function

it is a trinomial

<u>What is  standard form of a polynomial?</u>

When expressing a polynomial in its standard form, the greatest degree of terms are written first, followed by the next degree, and so on.

So, standard form is:

4x^5+3x^2+3

To find the degree of the polynomial, add up the exponents of each term and select the highest sum ( if there are more than 1 variable in single term) or highest power of variable

Degree = 5

In a polynomial, the leading term is the term with the highest power of x.

So, leading coefficient=4

The 5th degree polynomial is:

Quintic function

It has 3 terms. so, it is a trinomial

To learn more about the standard form of a polynomial from the given link

brainly.com/question/26552651

#SPJ1

4 0
1 year ago
Please help me with this question please!!<br><br> Slope of ionic bond (GREEN) =
Agata [3.3K]

Answer:

m=2

Step-by-step explanation:

(0,0) (5,10)

5 0
3 years ago
Any two conditions of an object to float on liquid ​
bixtya [17]

Answer:

it needs to be less dense than water and weight needs to be equal to buoyant force.

8 0
3 years ago
Daily low temperatures in Columbus, OH in January 2014 were approximately normally distributed with a mean of 15.45 and a standa
Alona [7]

Answer: 12.10

Step-by-step explanation:

Given : Mean : \mu = 15.45

Standard deviation : \sigma = 13.70

The formula to calculate the z-score :-

z=\dfrac{x-\mu}{\sigma}

For x= 5 degrees

z=\dfrac{5-15.45}{13.70}=-0.7627737226\approx-0.76

For x= 10 degrees

z=\dfrac{10-15.45}{13.70}=-0.397810218\approx-0.40

The P-value : P(-0.76

=0.3445783-0.2236273=0.120951\approx0.1210

In percent , 0.1210\times100=12.10\%

Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%

5 0
3 years ago
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