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AlexFokin [52]
2 years ago
5

The amount of water vapor in a given volume of air is ______________ .The amount of water vapor in the air at any one time depen

ds on ______________ . Warmer air holds ______________ water thancooler air. Clouds form when humidity is ______________ and thetemperature is ______________ . ______________ humidity is definedas the amount of water vapor in the air ______________ by the amountthat would have to be present in the same air to form a ______________ or condense on a surface. ______________ is related to the humidityof the previous day. The air temperature at which water vapor in the air ______________ onto cool surfaces is the dew point.
The words:
humidity
temperature
more
high
low
relative
divided
cloud
dew
condenses
if u answer this I sware u'll be brainliest bc this is so important, thank u u r soo kind and much appreciated if u please
God Bless
Chemistry
1 answer:
Eduardwww [97]2 years ago
8 0

Answer:

The amount of water vapor in a given volume of air is humidity.The amount of water vapor in the air at any one time depends on temperature . Warmer air holds more water than cooler air. Clouds form when humidity is low and thetemperature is high . Relative humidity is defined as the amount of water vapor in the air divided by the amount that would have to be present in the same air to form a cloud or condense on a surface. Dew is related to the humidity of the previous day. The air temperature at which water vapor in the air condenses onto cool surfaces is the dew point.

Explanation:

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Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=14.6L\\T_1=25.0^oC=(25+273)K=298K\\V_2=?\\T_2=220.0^0C=(220+273)K=493K

Putting values in above equation, we get:

\frac{14.6}{298K}=\frac{V_2}{493}\\\\V_2=24.1L

Thus the volume of the sample when heated to 220.0oC and the pressure is constant is 24.1 L

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