What this solving system of equations? x+y=-3 y=x^2+4x+1

Mathematics

2 answers:

Sedbober [7]2 years ago

5 0

Answer:

Step-by-step explanation:

y = -x-3

y = x^2 + 4x + 1

x^2 + 4x + 1 = -x-3

x^2 + 5x + 4 = 0

Quadratic Formula

x = [-5±√(5²-4⋅1⋅4)]/[2⋅1] = [-5±√9]/2 = [-5±3]/2 = 1,-4

(x,y) = (1,-4) of(-4,1)

emmainna [20.7K]2 years ago

3 0

Answer:

x = -4, y = 1

x = -1, y = -2

Step-by-step explanation:

(1) x + y = -3 (2) y = $x^{2} +4x + 1$

y = -x - 3 -x - 3 = $x^{2} +4x + 1$

$x^{2} + 5x + 4 = 0\\$

(x + 4)(x + 1) = 0

x = -4 or x = -1

y = -(-4) - 3 = 4 - 3 = 1

y = -(-1) - 3 = 1 - 3 = -2

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The pool is located at (0,0) to get to your house from the pool you walk three blocks west and one block north what ordered pair

ira [324]

Answer:

(-3, 1) quadrant II (2)

Step-by-step explanation:

An image of the coordinate plane is show. The quadrants start at the top right and move around in the counter-clockwise direction. The x-axis is horizontal (side to side) and y-axis is vertical (up and down). Starting at the origin of the coordinate plane (0, 0) and going three blocks west (left) would put you at -3 on the x-axis. If you then proceed to go north (up) +1, you would now be at point (-3, 1) which is a (-x, +y) or in quadrant II.