Vector B has x, y, and z components 4, 6, and 3, respectively.

Each roller under a conveyor belt has a radius of 0.5 meters. the rollers turn at a rate of 30 revolutions per minute. what is t

svp [43]

Distance in a minute=0.5 times 30=15 meters
distance in a second=15 divided by 60=0.25 meters per second
hope it helps

3 0

3 years ago

Read 2 more answers

Precipitation tends to be _______ on the _______ side of a mountain because water vapor _______ as it rises there.

Lera25 [3.4K]

Answer:

Higher, Windward side, Condenses

Explanation:

The Windward side refers to that side of a mountain that faces the direction from which the wind is blowing. In this direction, the moisture containing hot air blowing from a distant place moves upward and strikes the mountain at a greater height, where the air mass is thin and the temperature is relatively cold. As the temperature and pressure decrease with altitude, the hot uprising air cools and gradually condenses. This results in the occurrence of high precipitation over this region i.e. the windward side of the mountain.

Therefore, the precipitation is always higher on the windward side of a mountain as the hot air undergoes condensation at greater height as it rises upward.

6 0

4 years ago

It takes Harry 34 s to walk from x1 = -11 m to x2 = -54 m .

miss Akunina [59]

Missing question:
"What is his velocity? Please answer using two sig figs in m/s."

Solution
The relationship between velocity (v), space (S) and time (t) is
 $v= \frac{S}{t}$
The space covered by Harry is
 $S=x_1 - x_2 = -11 m-(-54 m)=43 m$
and so the velocity is
 $v= \frac{43 m}{34 s} =1.26 m/s$

4 0

4 years ago

Someone help me! you get 27 points if you get it right

pashok25 [27]

Answer:

1. D

2. D

3. A

The reason why your body goes right and the car car goes left is because your body tries to stay where it was, which is on the right. Your upper body doesn't feel a force and because of that continues in the same direction. Your lower half is pulled out from under you by seat friction to the left, leaving you leaning to the right.

8 0

3 years ago

A spaceship carrying a light clock moves at a speed of 0.960c relative to an observer on Earth. If the clock on the ship advance

aleksklad [387]

Answer:

(A) The time taken as measured by the observer on Earth is 0.96 s.

Explanation:

Given;

relative speed of spaceship to an observer on Earth, v = 0.960c

$(\frac{speed \ of \ spaceship}{speed \ of \ Earth}=\frac{V}{C} = 0.96 )$

time of the spaceship as it advances, t = 1.00 s

time of advance observed on Earth, t = ?

Speed = distance / time

Distance = speed x time

Assuming constant distance in the spaceship advancement;

$V_{space}*t_{space} = V_{Earth}*t_{Earth}\\\\\frac{V_{space}}{ V_{Earth}} = \frac{t_{Earth}}{t_{space}}\\\\ 0.96 = \frac{t_{Earth}}{1}\\\\t_{Earth} = 0.96 \ s$

Therefore, the time taken as measured by the observer on Earth is 0.96 s.

The correct option is "A" 0.96 s

3 0

4 years ago