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suter [353]
3 years ago
13

A store sells there varieties of cheese chddar, Gouda, and swiss. Each variety of cheese is available in two different styles sh

eredded or sliced. How many possible outcomes for the variety and style of cheese are there?

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
6 0
There are 6 possible outcomes.

1. Cheddar shredded.
2. Cheddar sliced.
3. Gouda shredded.
4. Grouda sliced.
5. Swiss shredded.
6. Swiss sliced.

Have a great day.
Don't forget to chose brainliest answer.
Diano4ka-milaya [45]3 years ago
5 0

There are 3 varieties of cheese (cheddar, Gouda, swiss) and 2 styles (shredded, sliced). You simply multiply those numbers: 3*2 = 6

Answer: 6

Here are the 6 possible combinations:

Combo 1: cheddar, shredded

Combo 2: cheddar, sliced

Combo 3: Gouda, shredded

Combo 4: Gouda, sliced

Combo 5: swiss, shredded

Combo 6: swiss, sliced

Each line shown above is exactly one possible combo.

You can decide to use a tree to help organize the information (see attached image). Note how there are 6 branches in the tree to represent the 6 combos

If there are a ton of combinations, then it would take a long time to list them all. Also, the tree would be a pain to create with so many branches. Fortunately, 6 is a small number to work with.

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VashaNatasha [74]

Answer:

10 Cups of Milk

Step-by-step explanation:

2/3  cup of milk --->10 cookies

  x  cup of milk --->150 cookies

x=((2/3)*150)/10=(2/3)*15=10 cups of milk

8 0
3 years ago
3x-7y=2 solve for x. Can you show how you do it?
guajiro [1.7K]
3x-7y=2 ; 3x=2+7y x=2x+7y/3
5 0
4 years ago
Consider this exponential equation:
ioda

Step-by-step explanation:

F( <em>x</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>(</em><em>3</em><em>)</em><em> </em><em>^</em><em> </em><em>x</em>

<em>Y</em><em> </em><em>intercept</em><em> </em>

<em>Let</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>1</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em>

<em>X</em><em> </em><em>intercept</em><em> </em>

<em>let</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>o</em>

<em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em>x</em>

<em>No</em><em> </em><em>x</em><em> </em><em>intercept</em><em>/</em><em> </em><em>zero</em>

<em>therefore</em><em> </em>

<em>Vertical</em><em> </em><em>intercept</em><em> </em><em>(</em><em>0</em><em>;</em><em> </em><em>5</em><em>)</em>

<em>Domain</em><em> </em><em>XER</em>

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4 0
3 years ago
"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that give
mestny [16]

Answer:

a. answer to a can be found in the attached file

b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=

0.24+0.06+0.05 = 0.35

c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its  overall probability of survival?

Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07

Step-by-step explanation:

"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that gives a 0.8 chance of seed survival, a medium-quality soil that gives a 0.3 chance of survival, and a low-quality soil that gives only a 0.1 chance of survival. These three soil types (high, medium, and low) are present in the habitat in proportions of 30:20:50, respectively. The probability that a seed lands on a particular soil type is proportional to the frequency of that type in the habitat. a. Draw a probability tree to determine the probabilities of survival under all possible circumstances. b. What is the probability of survival of the seed, assuming that it lands"c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?

a. Find the probability tree as attached below

b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=

0.24+0.06+0.05 = 0.35

c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its  overall probability of survival?

Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07

Download docx
7 0
3 years ago
The table shows three values of x and their corresponding values of f (x) for a linear function f, such that f (r) = 0 and f (0)
Rus_ich [418]

Using a linear function, it is found that the product rs is rs = 81.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

In this problem, when x changes by 68(from -64 to 68), y changes by -16(from 12 to -4), hence the slope is given by:

m = -16/64 = -0.25.

Hence:

y = -0.25x + b.

When x = 34, y = -4, hence this is used to find b.

-4 = -0.25(34) + b

b = 4.5.

Hence the function is:

y = -0.25x + 4.5.

f(r) = 0, hence:

-0.25x + 4.5 = 0

x = 4.5/0.25

x = 18

r = 18.

f (0) = s, hence s = 4.5.

Then the value of the product is:

rs = 18 x 4.5 = 81.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

7 0
2 years ago
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