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suter [353]
3 years ago
13

A store sells there varieties of cheese chddar, Gouda, and swiss. Each variety of cheese is available in two different styles sh

eredded or sliced. How many possible outcomes for the variety and style of cheese are there?

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
6 0
There are 6 possible outcomes.

1. Cheddar shredded.
2. Cheddar sliced.
3. Gouda shredded.
4. Grouda sliced.
5. Swiss shredded.
6. Swiss sliced.

Have a great day.
Don't forget to chose brainliest answer.
Diano4ka-milaya [45]3 years ago
5 0

There are 3 varieties of cheese (cheddar, Gouda, swiss) and 2 styles (shredded, sliced). You simply multiply those numbers: 3*2 = 6

Answer: 6

Here are the 6 possible combinations:

Combo 1: cheddar, shredded

Combo 2: cheddar, sliced

Combo 3: Gouda, shredded

Combo 4: Gouda, sliced

Combo 5: swiss, shredded

Combo 6: swiss, sliced

Each line shown above is exactly one possible combo.

You can decide to use a tree to help organize the information (see attached image). Note how there are 6 branches in the tree to represent the 6 combos

If there are a ton of combinations, then it would take a long time to list them all. Also, the tree would be a pain to create with so many branches. Fortunately, 6 is a small number to work with.

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7. Are the ordered pairs below an arithmetic sequence or geometric
DochEvi [55]

Answer:

8. Arithmetic Progression

9. f(9) = 300

Step-by-step explanation:

Given

\{(1,55)\ (2, 45)\ (3, 35)\ (4, 25)\}

Solving (8): Arithmetic or Geometric

We start by checking if it is arithmetic by checking for common difference (d).

d = y_2 - y_1 = y_3 - y_2 = y_4 - y_3

This gives:

d = 45 - 55 = 35 - 45 = 25 - 35

d = -10 = -10 = -10

d=-10

<em>Because the common difference is equal, then it is an arithmetic progression</em>

<em></em>

Solving (8):

f(n) = f(1) + f(n-1)

To find f(9), we substitute 9 for n

f(9) = f(1) + f(9-1)

f(9) = f(1) + f(8)

We need to solve for f(8); substitute 8 for n

f(8) = f(1) + f(8 - 1)

f(8) = f(1) + f(7)

We need to solve for f(7); substitute 7 for n

f(7) = f(1) + f(7 - 1)

f(7) = f(1) + f(6)

We need to solve for f(6); substitute 6 for n

f(6) = f(1) + f(6 - 1)

f(6) = f(1) + f(5)

We need to solve for f(5); substitute 6 for n

f(5) = f(1) + f(5 - 1)

f(5) = f(1) + f(4)

From the function, f(4) = 25 and f(1) = 55.

So:

f(5)=55 + 25

f(5)=80

f(6) = f(1) + f(5)

f(6) = 55 + 80

f(6) = 135

f(7) = f(1) + f(6)

f(7) = 55 + 135

f(7) = 190

f(8) = f(1) + f(7)

f(8) = 55 + 190

f(8) = 245

f(9) = f(1) + f(8)

f(9) = 55 + 245

f(9) = 300

8 0
3 years ago
Can someone help me plz I am not in high school I am 11 and I don't get percentages %
monitta

Answer:in decimal form it is 0.12. in 12/100

Step-by-step explanation:

4 0
3 years ago
Help meeee
Kazeer [188]

Answer:

100cm³

Step-by-step explanation:

3 0
3 years ago
What is the square root of PEMDAS?
Aleks04 [339]

Answer:

square roots fall under exponets

Step-by-step explanation:

5 0
2 years ago
I need help a problem 16
MakcuM [25]

Answer: The triangles are not congruent.

Step-by-step explanation:

We are given that the two triangles both contain a congruent angle and a congruent side. Additionally, the two triangles also share a side with each other, which is the center horizontal side (the one bisecting the two congruent angles). This "shared" side tells us that this side is congruent in both triangles, meaning that both triangles have two congruent sides with a non-included congruent angle among them.

However, because the two triangles only have two congruent sides, and the angle shared by each triangle is not included between the two sides, the triangle would be "congruent" by SSA, which is not a triangle congruency theorem or postulate.

Therefore, the two triangles are not congruent.

I hope this helps!

7 0
2 years ago
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